CODEWITHSUNDEEP
bash
ricky162
ricky162

Reputation: 1511

How to print out individual numbers after ordering an array in Bash?

I'm new to bash and having some issues printing out individual numbers after sorting an array. I have the following....

 for x  in ${array[@]}
               do
                  echo $x
               done| sort

This is the only way I was able to print out the entire array in order. Now I'm trying to print out a single item after it's been ordered so I tried....

for x  in ${array[@]}
                   do
                      echo ${array[2]}
                      exit
                   done| sort

But it prints the third item in the unordered array array instead. Any help?

Upvotes: 1

Views: 36

Answers (1)

Fazlin
Fazlin

Reputation: 2337

You are printing the variable and then trying to sort the ONLY variable that you have printed (in your case ${array[2]})

Try this:

sorted=($(printf '%s\n' "${array[@]}"|sort))
echo ${sorted[2]}

This sorts the array and stores it in another array sorted

Upvotes: 1

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