CODEWITHSUNDEEP
kernelopencl
Chopp
Chopp

Reputation: 69

OpenCL Invalid Kernel Name

I'm converting OpenCL code from my Mac to a Linux box with an NVIDIA Tesla K20c card and have run into a snag when building a simple kernel. My kernel code is this:

char kernel[1024] =
"#pragma OPENCL EXTENSION cl_khr_fp64: enable \
                                              \
kernel void diff(global double* u,            \
                  int N,                      \
                  double dx,                  \
                  global double* du)          \
{                                             \
    size_t i = get_global_id(0);              \
    int ip = (i+1)%N;                         \
    int im = (i+N-1)%N;                       \
    du[i] = (u[ip] - u[im])/dx/2.;            \
}";

I call this with:

const char* srccode = kernel;
cl_program program = clCreateProgramWithSource(context, 1, &srccode, NULL, &err);
err = clBuildProgram(program, 0, NULL, NULL, NULL, NULL);
kernel = clCreateKernel(program, "diff", &err);

clBuildProgram returns CL_SUCCESS and the log from clBuildProgramInfo is empty, but clCreateKernel returns CL_INVALID_KERNEL_NAME. Any idea why? I've been banging at this a while and can't find anything. If I change all the doubles to floats and remove the pragma the problem goes away and it works correctly. So is the pragma to blame? If so, how do I do it correctly?

Upvotes: 1

Views: 2924

Answers (1)

doqtor
doqtor

Reputation: 8484

The whole kernel[1024] string will end up in one line which is fine for the kernel definition but not for pragma - there you need the end line character. Fixed version would look like this:

char kernel[1024] =
"#pragma OPENCL EXTENSION cl_khr_fp64: enable \n\
                                              \
kernel void diff(global double* u,            \
                  int N,                      \
                  double dx,                  \
                  global double* du)          \
{                                             \
    size_t i = get_global_id(0);              \
    int ip = (i+1)%N;                         \
    int im = (i+N-1)%N;                       \
    du[i] = (u[ip] - u[im])/dx/2.;            \
}";

Upvotes: 3

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