Reputation: 15036
How do I programmatically list all of the projects in a solution? I'll take a script, command-line, or API calls.
Upvotes: 55
Views: 42184
Reputation: 802
Here is a modified approach I used to look at the problem from a Solution-first stance:
Function Get-ProjectReferences ($rootFolder) {
$ns = @{ defaultNamespace = "http://schemas.microsoft.com/developer/msbuild/2003" }
$solutionFilesWithContent = Get-ChildItem $rootFolder -Filter *.sln -Recurse |
ForEach-Object {
New-Object PSObject -Property @{
SolutionFile = $_;
SolutionContent = Get-Content $_;
}
}
$projectFilesWithContent = Get-ChildItem $rootFolder -Filter *.csproj -Recurse |
ForEach-Object {
New-Object PSObject -Property @{
ProjectFile = $_;
ProjectContent = [xml](Get-Content $_);
}
}
$solutionFilesWithContent | ForEach-Object {
$solutionFileWithContent = $_
$projectsInSolutionStrings = $solutionFileWithContent.SolutionContent | Select-String 'Project\('
$projectsInSolution = $projectsInSolutionStrings |
ForEach-Object {
$projectParts = $_ -Split '[,=]' | ForEach-Object { $_.Trim('[ "{}]') };
if ($projectParts[2].Contains(".csproj")) {
New-Object PSObject -Property @{
Name = $projectParts[1];
File = $projectParts[2];
Guid = $projectParts[3];
}
}
}
$projectsInSolution | ForEach-Object {
$projectFileSearchName = $_.Name + ".csproj"
$projectInSolutionFile = $projectFilesWithContent | Where-Object { $_.ProjectFile.Name -eq $projectFileSearchName } | Select-Object -First 1
if (($null -eq $projectInSolutionFile) -and ($null -eq $projectInSolutionFile.ProjectContent)) {
Write-Host "Project was null"
}
else {
$projectInSolutionName = $projectInSolutionFile.ProjectFile | Select-Object -ExpandProperty BaseName
$projectReferences = $projectInSolutionFile.ProjectContent | Select-Xml '//defaultNamespace:ProjectReference/defaultNamespace:Name' -Namespace $ns | Select-Object -ExpandProperty Node | Select-Object -ExpandProperty "#text"
$projectTarget = $projectInSolutionFile.ProjectContent | Select-Xml "//defaultNamespace:TargetFrameworkVersion" -Namespace $ns | Select-Object -ExpandProperty Node | Select-Object -ExpandProperty "#text"
$projectReferences | ForEach-Object {
$projectFileName = $_ + ".csproj"
$referenceProjectFile = $projectFilesWithContent | Where-Object { $_.ProjectFile.Name -eq $projectFileName } | Select-Object -First 1
if ($null -eq $referenceProjectFile) {
$referenceProjectTarget = "Unknown"
}
else {
$referenceProjectTarget = $referenceProjectFile.ProjectContent | Select-Xml "//defaultNamespace:TargetFrameworkVersion" -Namespace $ns | Select-Object -ExpandProperty Node | Select-Object -ExpandProperty "#text"
}
"[" + $solutionFileWithContent.SolutionFile.Name + "] -> [" + $projectInSolutionName + " " + $projectTarget + "] -> [" + $_ + " " + $referenceProjectTarget + "]"
}
}
}
}
}
Get-ProjectReferences "C:\src\repos\MyRepo" | Out-File "C:\src\repos\FrameworkDependencyAnalysis\FrameworkDependencyAnalysis.txt"
Upvotes: 0
Reputation: 111
from powershelll and in the solution's folder write
dotnet sln list
Upvotes: 8
Reputation: 1156
To expand on the answer by @brianpeiris:
Function Global:Get-ProjectInSolution {
[CmdletBinding()] param (
[Parameter()][string]$Solution
)
$SolutionPath = Join-Path (Get-Location) $Solution
$SolutionFile = Get-Item $SolutionPath
$SolutionFolder = $SolutionFile.Directory.FullName
Get-Content $Solution |
Select-String 'Project\(' |
ForEach-Object {
$projectParts = $_ -Split '[,=]' | ForEach-Object { $_.Trim('[ "{}]') }
[PSCustomObject]@{
File = $projectParts[2]
Guid = $projectParts[3]
Name = $projectParts[1]
}
} |
Where-Object File -match "csproj$" |
ForEach-Object {
Add-Member -InputObject $_ -NotePropertyName FullName -NotePropertyValue (Join-Path $SolutionFolder $_.File) -PassThru
}
}
This filters to only .csproj
files and adds the full path of each based on the File
field and the path containing the sln
file.
Use Get-ProjectInSolution MySolution.sln | Select-Object FullName
to get each of the full file paths.
The reason I wanted the full path was to be able to access the packages.config
files beside each project file and then get the packages from all of them:
Get-ProjectInSolution MySolution.sln |
%{Join-Path ($_.FullName | Split-Path) packages.config} |
%{select-xml "//package[@id]" $_ | %{$_.Node.GetAttribute("id")}} |
select -unique
Upvotes: 0
Reputation: 1237
I know that this is maybe already answered question, but I would like to share my approach of reading sln file. Also during run time I am determining if project is Test project or not
function ReadSolutionFile($solutionName)
{
$startTime = (Get-Date).Millisecond
Write-Host "---------------Read Start---------------"
$solutionProjects = @()
dotnet sln "$solutionName.sln" list | ForEach-Object{
if($_ -Match ".csproj" )
{
#$projData = ($projectString -split '\\')
$proj = New-Object PSObject -Property @{
Project = [string]$_;
IsTestProject = If ([string]$_ -Match "test") {$True} Else {$False}
}
$solutionProjects += $proj
}
}
Write-Host "---------------Read finish---------------"
$solutionProjects
$finishTime = (Get-Date).Millisecond
Write-Host "Script run time: $($finishTime-$startTime) mil"
}
Hope this will be helpfull.
Upvotes: 2
Reputation: 1214
You can use the EnvDTE.Solution.Projects object to programmatically get access to the projects in a solution.
One gotcha though is that if you have any SolutionFolders in your solution, any projects in these folders are not shown in the above collection.
I've written an article including a code sample on how to get all projects regardless of any solutionfolders
Upvotes: 12
Reputation: 1124
Currently you can use Package Manager Console in VS to obtain that info. Use powershell Get-Project
command
Get-Project -All
Upvotes: 11
Reputation: 1083
The trick is to choose the right MsBuild.dll. Under VS2017 it is indeed "C:\Program Files (x86)\Microsoft Visual Studio\2017\Professional\MSBuild\15.0\Bin\amd64\Microsoft.Build.dll" (Dont use the standard Msbuild ddl in references. Browse to this path)
c#:
var solutionFile =
SolutionFile.Parse(@"c:\NuGetApp1\NuGetApp1.sln");//your solution full path name
var projectsInSolution = solutionFile.ProjectsInOrder;
foreach(var project in projectsInSolution)
{
switch (project.ProjectType)
{
case SolutionProjectType.KnownToBeMSBuildFormat:
{
break;
}
case SolutionProjectType.SolutionFolder:
{
break;
}
}
}
powershell:
Add-Type -Path (${env:ProgramFiles(x86)} + '\Microsoft Visual
Studio\2017\Professional\MSBuild\15.0\Bin\amd64\Microsoft.Build.dll')
$slnPath = 'c:\NuGetApp1\NuGetApp1.sln'
$slnFile = [Microsoft.Build.Construction.SolutionFile]::Parse($slnPath)
$pjcts = $slnFile.ProjectsInOrder
foreach ($item in $pjcts)
{
switch($item.ProjectType)
{
'KnownToBeMSBuildFormat'{Write-Host Project : $item.ProjectName}
'SolutionFolder'{Write-Host Solution Folder : $item.ProjectName}
}
}
Upvotes: 14
Reputation: 351
There's a really elegant solution here: Parsing Visual Studio Solution files
The answer by John Leidegren involves wrapping the internal Microsoft.Build.Construction.SolutionParser
class.
Upvotes: 3
Reputation: 426
Since Visual Studio 2013 the Microsoft.Build.dll provides a SolutionFile object with some very handy functions.
Here's an example of using the v14.0 version to list the relative path of all the projects in the order they appear in the solution.
Add-Type -Path (${env:ProgramFiles(x86)} + '\Reference Assemblies\Microsoft\MSBuild\v14.0\Microsoft.Build.dll')
$solutionFile = '<FULL PATH TO SOLUTION FILE>'
$solution = [Microsoft.Build.Construction.SolutionFile] $solutionFile
($solution.ProjectsInOrder | Where-Object {$_.ProjectType -eq 'KnownToBeMSBuildFormat'}).RelativePath
There are plenty of other properties on the project object (ProjectName, AbsolutePath, configurations etc) that may be of use. In the above example I used the ProjectType to filter out Solution Folders.
Upvotes: 4
Reputation:
If you need to do this on a non Windows machine, you can use the following Bash command:
grep "Project(" NameOfYourSolution.sln | cut -d'"' -f4
Upvotes: 1
Reputation: 7017
var Content = File.ReadAllText(SlnPath);
Regex projReg = new Regex(
"Project\\(\"\\{[\\w-]*\\}\"\\) = \"([\\w _]*.*)\", \"(.*\\.(cs|vcx|vb)proj)\""
, RegexOptions.Compiled);
var matches = projReg.Matches(Content).Cast<Match>();
var Projects = matches.Select(x => x.Groups[2].Value).ToList();
for (int i = 0; i < Projects.Count; ++i)
{
if (!Path.IsPathRooted(Projects[i]))
Projects[i] = Path.Combine(Path.GetDirectoryName(SlnPath),
Projects[i]);
Projects[i] = Path.GetFullPath(Projects[i]);
}
Edit: Amended the regex to include the ".*" as per the comment by Kumar Vaibhav
Upvotes: 21
Reputation: 10795
Here's a PowerShell script that retrieves project details from a .sln file:
Get-Content 'Foo.sln' |
Select-String 'Project\(' |
ForEach-Object {
$projectParts = $_ -Split '[,=]' | ForEach-Object { $_.Trim('[ "{}]') };
New-Object PSObject -Property @{
Name = $projectParts[1];
File = $projectParts[2];
Guid = $projectParts[3]
}
}
Upvotes: 76
Reputation: 13456
just read the list from *.sln file. There are "Project"-"EndProject" sections.
Here is an article from MSDN.
Upvotes: 5