Spring Boot - Loading Initial Data

Question

I'm wondering what the best way to load initial database data before the application starts? What I'm looking for is something that will fill my H2 database with data.

For example, I have a domain model "User" I can access users by going to /users but initially there won't be any users in the database so I have to create them. Is there anyway to fill the database with data automatically?

At the moment I have a Bean that gets instantiated by the container and creates users for me.

Example:

@Component
public class DataLoader {

    private UserRepository userRepository;

    @Autowired
    public DataLoader(UserRepository userRepository) {
        this.userRepository = userRepository;
        LoadUsers();
    }

    private void LoadUsers() {
        userRepository.save(new User("lala", "lala", "lala"));
    }
}

But I very much doubt that is the best way of doing it. Or is it?

Answer 1

You can create a data.sql file in your src/main/resources folder and it will be automatically executed on startup. In this file you can add some insert statements, eg.:

INSERT INTO users (username, firstname, lastname) VALUES
  ('lala', 'lala', 'lala'),
  ('lolo', 'lolo', 'lolo');

---

Similarly, you can create a schema.sql file (or schema-h2.sql) as well to create your schema:

CREATE TABLE task (
  id          INTEGER PRIMARY KEY,
  description VARCHAR(64) NOT NULL,
  completed   BIT NOT NULL);

Though normally you shouldn't have to do this since Spring boot already configures Hibernate to create your schema based on your entities for an in memory database. If you really want to use schema.sql you'll have to disable this feature by adding this to your application.properties:

spring.jpa.hibernate.ddl-auto=none

More information can be found at the documentation about Database initialization.

---

If you're using Spring Boot 2, database initialization only works for embedded databases (H2, HSQLDB, ...). If you want to use it for other databases as well, you need to change the initialization mode property:

spring.sql.init.mode=always # Spring Boot >=v2.5.0
spring.datasource.initialization-mode=always # Spring Boot <v2.5.0

---

If you're using multiple database vendors, you can name your file data-h2.sql or data-mysql.sql depending on which database platform you want to use.

To make that work, you'll have to configure the datasource platform property:

spring.sql.init.platform=h2 # Spring Boot >=v2.5.0
spring.datasource.platform=h2 # Spring Boot <v2.5.0

Answer 2

You can add a spring.datasource.data property to application.yml (or application.properties) listing the SQL files you want to run. Like this:

spring:
  datasource:
    data: classpath:accounts.sql, classpath:books.sql, classpath:reviews.sql

# or (depending on Spring Boot version)

spring:
  sql:
    init:
      data-locations: classpath:accounts.sql, classpath:books.sql, file:reviews.sql

The SQL insert statements in each of these files will then be run, allowing you to keep things tidy.

If you put the files in the classpath, for example in src/main/resources they will be applied. Or replace classpath: with file: and use an absolute path to the file.

If you want to run DDL type SQL then use:

spring:
  datasource:
    schema: classpath:create_account_table.sql

# depending on Spring version

spring:
  sql:
    init:
      schema-locations: classpath:create_account_table.sql 

Note: These solutions are great to get you up and running quickly, however for a more production ready solution it would be worth looking at a framework such as flyway, or liquibase. These frameworks integrate well with Spring, and provide a quick, consistent, version-controlled means of initialising schema, and standing-data.

Answer 3

If you want to do insert quick some queries, you can do with h2 data.sql queries as well

application.properties include:

spring.jpa.show-sql=true
spring.h2.console.enabled=true
spring.datasource.url=jdbc:h2:mem:testdb

#This directs the data.sql file and help it to run
spring.sql.init.data-locations=classpath:data.sql
spring.jpa.defer-datasource-initialization=true

data.sql file include:

INSERT INTO todo (id, username, description, target_date, is_done) VALUES (10001, 'lighteducation', 'Learn dance', CURRENT_DATE ,false);

INSERT INTO todo (id, username, description, target_date, is_done) VALUES (10002, 'lighteducation', 'Learn Angular14', CURRENT_DATE, false);

INSERT INTO todo (id, username, description, target_date, is_done) VALUES (10003, 'lighteducation', 'Learn Microservices', CURRENT_DATE,false);

P.S.: data.sql file should be inside src/main/resources

Your @Entity include

@Getter
@Setter
@AllArgsConstructor
@ToString
@Entity
public class Todo {
    @Id
    @GeneratedValue
    private Long id;

    private String username;
    private String description;
    private Date targetDate;
    private boolean isDone;

    protected Todo() {

    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;
        Todo todo = (Todo) o;
        return id == todo.id;
    }

    @Override
    public int hashCode() {
        return Objects.hash(id);
    }
}

That is it basically. it will be in memory, it means when you restart application data will arese and will be again same as queries show.

But it is easy for quick check

also you can access the path with http://localhost:8080/h2-console/ or you can edit the path from .properties file

Answer 4

For those using MysqlDriver, I tried using Init attribute of @bean annotation and it works.

After created the Schema and Data sql file in the path of resources\Scripts

Add the line in application.properties

spring.jpa.hibernate.ddl-auto=none

Edit the Application content:

package com.spring_mvaen.demo;

import org.springframework.boot.CommandLineRunner;

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.Bean;
import org.springframework.core.io.ClassPathResource;
import org.springframework.core.io.Resource;
import org.springframework.jdbc.datasource.DriverManagerDataSource;
import org.springframework.jdbc.datasource.init.DatabasePopulator;
import org.springframework.jdbc.datasource.init.DatabasePopulatorUtils;
import org.springframework.jdbc.datasource.init.ResourceDatabasePopulator;

@SpringBootApplication
public class DemoApplication implements CommandLineRunner {

  public static void main(String[] args) {
    SpringApplication.run(DemoApplication.class, args);
  }
  @Override
  public void run(String... arg0) throws Exception {
    System.out.println("Hello world from Command Line Runner");
  }

  @Bean(name = "dataSource")
  public DriverManagerDataSource dataSource() {
    DriverManagerDataSource dataSource = new DriverManagerDataSource();
    dataSource.setDriverClassName("com.mysql.cj.jdbc.Driver");
    dataSource.setUrl("jdbc:mysql://localhost:3306/db_spring_rest?useUnicode=true&useLegacyDatetimeCode=fa    lse&serverTimezone=UTC&createDatabaseIfNotExist=true&allowPublicKeyRetrieval=true&useSSL=false");
    dataSource.setUsername("root");
    dataSource.setPassword("root");

    // schema init
    Resource initSchema = new ClassPathResource("scripts/schema.sql");
    Resource initData = new ClassPathResource("scripts/data.sql");
    DatabasePopulator databasePopulator = new ResourceDatabasePopulator(initSchema, initData);
    DatabasePopulatorUtils.execute(databasePopulator, dataSource);

    return dataSource;
  }


}

Answer 5

If you came here and nothing seems to work for you, then it might be the case that you are affected from some changes that were introduced with Spring Boot 2.5 and onwards.

Here is the total set of properties which I use for postgresql.

spring:
  sql.init.mode: always   <-----------------
  datasource:
    url: jdbc:postgresql://localhost:5432/products
    username: 
    password: 
  jpa:
    defer-datasource-initialization: true  <------------------
    hibernate:
      ddl-auto: create-drop   <----------------
    database-platform: org.hibernate.dialect.PostgreSQLDialect

I have also marked with <--- the relevant properties for the current topic in order to achieve the following.

• ORM vendor will create database schema for you from Java Entities model.
• After database schema is created, initial data will be loaded to database from the file data.sql

Ps: Don't forget to add the file with initial data, data.sql under src/main/resources

Also as reference: Spring Boot 2.5 release notes

Answer 6

There are multiple ways how to achieve this. I prefer to use one of following options:

Option 1: Initializing with CommandLineRunner bean:

@Bean
public CommandLineRunner loadData(CustomerRepository repository) {
    return (args) -> {
        // save a couple of customers
        repository.save(new Customer("Jack", "Bauer"));
        repository.save(new Customer("Chloe", "O'Brian"));
        repository.save(new Customer("Kim", "Bauer"));
        repository.save(new Customer("David", "Palmer"));
        repository.save(new Customer("Michelle", "Dessler"));

        // fetch all customers
        log.info("Customers found with findAll():");
        log.info("-------------------------------");
        for (Customer customer : repository.findAll()) {
            log.info(customer.toString());
        }
        log.info("");

        // fetch an individual customer by ID
        Customer customer = repository.findOne(1L);
        log.info("Customer found with findOne(1L):");
        log.info("--------------------------------");
        log.info(customer.toString());
        log.info("");

        // fetch customers by last name
        log.info("Customer found with findByLastNameStartsWithIgnoreCase('Bauer'):");
        log.info("--------------------------------------------");
        for (Customer bauer : repository
                .findByLastNameStartsWithIgnoreCase("Bauer")) {
            log.info(bauer.toString());
        }
        log.info("");
    }
}

Option 2: Initializing with schema and data SQL scripts

Prerequisites:

application.properties

spring.jpa.hibernate.ddl-auto=none

Explanation:

Without ddl-auto SQL scripts will be ignored by Hibernate and trigger default behavior - scanning project for @Entity and/or @Table annotated classes.

Then, in your MyApplication class paste this:

@Bean(name = "dataSource")
public DriverManagerDataSource dataSource() {
    DriverManagerDataSource dataSource = new DriverManagerDataSource();
    dataSource.setDriverClassName("org.h2.Driver");
    dataSource.setUrl("jdbc:h2:~/myDB;MV_STORE=false");
    dataSource.setUsername("sa");
    dataSource.setPassword("");

    // schema init
    Resource initSchema = new ClassPathResource("scripts/schema-h2.sql");
    Resource initData = new ClassPathResource("scripts/data-h2.sql");
    DatabasePopulator databasePopulator = new ResourceDatabasePopulator(initSchema, initData);
    DatabasePopulatorUtils.execute(databasePopulator, dataSource);

    return dataSource;
}

Where scripts folder is located under resources folder (IntelliJ Idea)

Hope it helps someone

Update 04-2021: Both options are great to combine with Spring Profiles as this will help you to avoid creating additional config files making your life as the developer easy.

Answer 7

I created a library that facilitates initial/demo data loading in a Spring Boot application. You can find it at https://github.com/piotrpolak/spring-boot-data-fixtures

Once the data fixtures starter is on the classpath, it will automatically try to load DICTIONARY data upon application startup (this behavior can be controlled by properties) - all you need to do is to register a bean implementing DataFixture.

I find loading initial data by code superior to loading it using SQL scripts:

• the logic of your fixtures lives close to your application logic/domain model and it is subject to refactoring as your domain evolves
• you benefit from incremental demo data updates - imagine a QA environment with some user data (that needs not to be lost after application deploy) but at the same time you want to add data for the new features you developed

Example data fixture:

/**
 * You can have as many fixture classes as you want.
 * @Order annotation is respected for the fixtures belonging to the same set.
 * You can make your demo database to be incrementally updated with fresh data
 * each time the application is redeployed - all you need to do is to write
 * a good condition in `canBeLoaded()` method.
 */
@Component
public class InitialDataFixture implements DataFixture {

    private final LanguageRepository languageRepository;

    // ...

    @Override
    public DataFixtureSet getSet() {
      return DataFixtureSet.DICTIONARY;
    }

    /**
     * We want to make sure the fixture is applied once and once only.
     * A more sophisticated condition can be used to create incremental demo data
     * over time without the need to reset the QA database (for example).
     */
    @Override
    public boolean canBeLoaded() {
      return languageRepository.size() == 0;
    }

    /**
     * The actual application of the fixture.
     * Assuming that data fixtures are registered as beans, this method can call
     * other services and/or repositories.
     */
    @Override
    public void load() {
      languageRepository.saveAll(Arrays.asList(
          new Language("en-US"), new Language("pl-PL")));
    }
}

The concept is inspired by the Symfony Doctrine Data Fixtures bundle.

Answer 8

One possibility is using incorrect JDBC URL. make sure it is jdbc:h2:mem:testdb

Answer 9

You can use the below code. In the following code a database insertion occurs during the startup of the spring boot application.

@SpringBootApplication
public class Application implements CommandLineRunner {
    
    @Autowired
    private IService<Car> service;

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }

    @Override
    public void run(String... args) throws Exception {
        for(int i=1; i<=1000; i++) {
            Car car = new Car();
            car.setName("Car Name "+i);
            book.setPrice(50 + i);
            service.saveOrUpdate(car);
        }
    }

}

Answer 10

You're almost there!

@Component
public class DataLoader implements CommandLineRunner {

    private UserRepository userRepository;

    public DataLoader(UserRepository userRepository) {
        this.userRepository = userRepository;
    }

    @Override
    public void run(String... args) throws Exception {
         LoadUsers()
    }

    private void LoadUsers() {
        userRepository.save(new User("lala", "lala", "lala"));
    }
}

Answer 11

If you want to insert only few rows and u have JPA Setup. You can use below

    @SpringBootApplication
        @Slf4j
        public class HospitalManagementApplication {

            public static void main(String[] args) {
                SpringApplication.run(HospitalManagementApplication.class, args);
            }            

            @Bean
            ApplicationRunner init(PatientRepository repository) {
                return (ApplicationArguments args) ->  dataSetup(repository);
            } 

            public void dataSetup(PatientRepository repository){
            //inserts

     }

Answer 12

you can register and event listener to achieve that like below:

@EventListener
public void seed(ContextRefreshedEvent event) {
    userRepository.save(new User("lala", "lala", "lala"));
}

When the ContextRefreshEvent is fired, we get access to all autowired beans in the application — including models and repositories.

Answer 13

I solved similar problem this way:

@Component
public class DataLoader {

    @Autowired
    private UserRepository userRepository;

    //method invoked during the startup
    @PostConstruct
    public void loadData() {
        userRepository.save(new User("user"));
    }

    //method invoked during the shutdown
    @PreDestroy
    public void removeData() {
        userRepository.deleteAll();
    }
}

Answer 14

In Spring Boot 2 data.sql was not working with me as in spring boot 1.5

import.sql

In addition, a file named import.sql in the root of the classpath is executed on startup if Hibernate creates the schema from scratch (that is, if the ddl-auto property is set to create or create-drop).

Note very important if you insert Keys cannot be duplicated do not use ddl-auto property is set to update because with each restart will insert same data again

For more information you vist spring websit

https://docs.spring.io/spring-boot/docs/current/reference/html/howto-database-initialization.html

Answer 15

If someone are struggling in make this to work even following the accepted answer, for me only work adding in my src/test/resources/application.yml the H2 datasource details:

spring:
  datasource:
    platform: h2
    url: jdbc:h2:mem:test;DB_CLOSE_DELAY=-1
    driver-class-name: org.h2.Driver
    username: sa
    password:

Answer 16

The most compact (for dynamic data) put @mathias-dpunkt solution into MainApp (with Lombok @AllArgsConstructor):

@SpringBootApplication
@AllArgsConstructor
public class RestaurantVotingApplication implements ApplicationRunner {
  private final VoteRepository voteRepository;
  private final UserRepository userRepository;

  public static void main(String[] args) {
    SpringApplication.run(RestaurantVotingApplication.class, args);
  }

  @Override
  public void run(ApplicationArguments args) {
    voteRepository.save(new Vote(userRepository.getOne(1), LocalDate.now(), LocalTime.now()));
  }
}

Answer 17

This will also work.

    @Bean
    CommandLineRunner init (StudentRepo studentRepo){
        return args -> {
            // Adding two students objects
            List<String> names = Arrays.asList("udara", "sampath");
            names.forEach(name -> studentRepo.save(new Student(name)));
        };
    }

Answer 18

Here is the way I got that:

@Component
public class ApplicationStartup implements ApplicationListener<ApplicationReadyEvent> {

    /**
     * This event is executed as late as conceivably possible to indicate that
     * the application is ready to service requests.
     */

    @Autowired
    private MovieRepositoryImpl movieRepository;

    @Override
    public void onApplicationEvent(final ApplicationReadyEvent event) {
        seedData();
    }

    private void seedData() {
        movieRepository.save(new Movie("Example"));

        // ... add more code
    }

}

Thanks to the author of this article:

http://blog.netgloo.com/2014/11/13/run-code-at-spring-boot-startup/

Answer 19

You can use something like this:

@SpringBootApplication  
public class Application {

@Autowired
private UserRepository userRepository;

public static void main(String[] args) {
    SpringApplication.run(Application.class, args);
}

@Bean
InitializingBean sendDatabase() {
    return () -> {
        userRepository.save(new User("John"));
        userRepository.save(new User("Rambo"));
      };
   }
}

Answer 20

If I just want to insert simple test data I often implement a ApplicationRunner. Implementations of this interface are run at application startup and can use e.g. a autowired repository to insert some test data.

I think such an implementation would be slightly more explicit than yours because the interface implies that your implementation contains something you would like to do directly after your application is ready.

Your implementation would look sth. like this:

@Component
public class DataLoader implements ApplicationRunner {

    private UserRepository userRepository;

    @Autowired
    public DataLoader(UserRepository userRepository) {
        this.userRepository = userRepository;
    }

    public void run(ApplicationArguments args) {
        userRepository.save(new User("lala", "lala", "lala"));
    }
}

Answer 21

You can simply create a import.sql file in src/main/resources and Hibernate will execute it when the schema is created.

Answer 22

Spring Boot allows you to use a simple script to initialize your database, using Spring Batch.

Still, if you want to use something a bit more elaborated to manage DB versions and so on, Spring Boot integrates well with Flyway.

See also:

• Spring Boot Database initialization