CODEWITHSUNDEEP
bashmacos
I0_ol
I0_ol

Reputation: 1109

how to remove lines containing only numbers, special characters or blanks after a delimiter

The following code:

#!/bin/bash

osascript -e \
'tell application "Google_Chrome" to tell tab 1 of window 1 \
set t to execute javascript "document.body.innerText" \
end tell' | grep ':'

Results in output: 

line1:blah blah 
line2:blah 123 
line3: 
line4:[456] blah
Line5:blah blah
line6:[789]
line 7:

The desired output:

line1:blah blah 
line2:blah 123 
line4:[456] blah

I can use cut -d : -f1 to get just the left side and cut -d : -f2 to get just right side. But I can't seem to figure out how to remove blank lines or lines with only numbers and/or special characters while still preserving the structure of data.

To the best of my knowledge, what I'm trying to achieve follows this specific set of rules:

Any ideas how to accomplish this?

Upvotes: 1

Views: 323

Answers (1)

anubhava
anubhava

Reputation: 784958

Replace your grep with this:

... | grep -E '^[a-z0-9_]+:[^a-zA-Z]*[a-zA-Z]'

line1:blah blah
line2:blah 123
line4:[456] blah

This will meet your requirements of allowing only [a-z0-9_] characters on left of : and at least one of [a-zA-Z] on RHS of :.

Upvotes: 3

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