Reputation: 4491
From a lambda implemented api gateway resource, how to get the original request URI. Or even just the original path?
Lacking a better way I'm currently using the following three variables that I pass down to the lambda using the default request template:
$context.resourcePath contains the path with variable names ex: "/blah/{var}"
$input.params().path contains the variable names and values ex: {"var":"something"}
$context.stage contains the stage ex: "prod"
That's quite a hassle since it requires path variable substitution to get the original call path:
/prod/blah/something
How can I get the original URL or URI?
Upvotes: 7
Views: 1983
Reputation: 1
I found a 'workaround'.
If you create a custom domain name with a BasePathMapping, and call the API using this custom domain, the original request uri actually has your stage name in there:
Call directly to the API gateway:
curl -v 'https://some-id.execute-api.eu-central-1.amazonaws.com/v1/ping'
...
request.url: https://some-id.execute-api.eu-central-1.amazonaws.com/ping'
But if we call it through te custom domain (which is actually a cloudfront distribution):
curl -v -X GET https://api.our.domain.name.com/v1/ping
...
request.url: https://api.our.domain.name.com/v1/ping
In my opinion, the direct call gives you an INCORRECT request url in the lambda function, as the url very clearly has the stage name in there.
This breaks the routing middleware of at least flask.
Any update on the feature request?
Upvotes: 0
Reputation: 3745
I'm not finding anything in the documentation that lets you get the original call URI. I can add a feature request to consider adding it. Can you describe your use case. Why do you want to get the original URI?
Upvotes: 3