TrotlOtl
TrotlOtl

Reputation: 103

How to add new rows to GridView

i'm making ASP.net application and i want to have some kind of table there. I tried using Grindview, but when i try to add second new row (from code), the second row replaces first row.

here is code:

DataTable dt = new DataTable();

            if (dt.Columns.Count == 0)
            {
                dt.Columns.Add("thing", typeof(string));
                dt.Columns.Add("thing2", typeof(string));
            }
            DataRow NewRow = dt.NewRow();
            NewRow[0] = label1.Text;
            NewRow[1] = label2.Text;
            dt.Rows.Add(NewRow);
            GridView1.DataSource = dt;
            GridView1.DataBind();

I'm expecting Gridview with 2 rows and button which gives you new row with every click.

Upvotes: 4

Views: 15343

Answers (3)

Antoine Pelletier
Antoine Pelletier

Reputation: 3316

if you have your front hand HTML asp.net code that define your gridview's style (here's an exemple) :

 <asp:GridView ID="grvModel"  runat="server" AlternatingRowStyle-BackColor="#eeeeee" BackColor="#aaccff"  AutoGenerateColumns="false">
    <Columns>

        <asp:TemplateField >
                <ItemTemplate>
                    <asp:Button id="btnDel" CommandName="Delete" OnClientClick="btnDel_click" runat="server"Text="Delete" />
                </ItemTemplate>
         </asp:TemplateField>

        <asp:TemplateField >
                <ItemTemplate>
                    <asp:TextBox runat="server" ID="lblWrite" Text='write here' />
                </ItemTemplate>
         </asp:TemplateField>
    </Columns>
 </asp:GridView>

Then all you have to do is create a List<> of object and bind it to your gridView, if you want to add somthing, just add to the list and bind it again (hers's an exemple) :

List<aClass> classList;

protected void BindFirstTime(object sender, EventArgs e)
{
    classList= new List<aClass>();
    classList.Add(new aClass("one"));
    classList.Add(new aClass("two"));
    Grv.DataSource = classList;
    Grv.DataBind();
}

protected void AddObject(object sender, EventArgs e)
{
    classList.Add(new aClass("three or more !"));
    Grv.DataSource = classList;
    Grv.DataBind();
}

This is the simple way for me, hope it helps.

Upvotes: 1

devlin carnate
devlin carnate

Reputation: 8592

You can add rows using a loop, where you create the row, add the content and then add the row to the datatable.

DataTable dt = new DataTable();

if (dt.Columns.Count == 0)
{
     dt.Columns.Add("thing", typeof(string));
     dt.Columns.Add("thing2", typeof(string));
}

for(int i = 0; i < 3; i++)
{
     DataRow dr = dt.NewRow();
     dr[0] = "foo";
     dr[1] = "bar";
     dt.Rows.Add(dr);
}

Then bind the datatable to your GridView:

GridView1.DataSource = dt;
GridViewl.DataBind();

Upvotes: 1

user1599615
user1599615

Reputation:

I dont know what you exactly asking or trying to do but this might help

  protected void Button1_Click(object sender, EventArgs e)

  {

   DataTable dt = new DataTable();

   if (dt.Columns.Count == 0)
   {
       dt.Columns.Add("nameofcolumn1", typeof(string));
       dt.Columns.Add("nameofcolumn2", typeof(string));
       dt.Columns.Add("nameofcolumn3", typeof(string));
   }

   DataRow NewRow = dt.NewRow();
   NewRow[0] = value1;
   NewRow[ 1] = value2;
   dt.Rows.Add(NewRow); 
   GridView1.DataSource = dt;
   GridViewl.DataBind();

   }

visit this link also Add row datagridview at every button click

Upvotes: 1

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