Reputation: 167
I have a situation where I need to render a table using Datatables. However, I need to be able to sort it horizontally (left to right) instead of vertically (top to bottom). Is there any way I can do this?
Illustration: Columns are A,B,C,D,E. Rows are R1,R2,R3,R4...R30. I don't want to sort A to E, but I do want to sort any one of R1 to R30 so that A-E gets rearranged. For instance, for R1, the ascending order of values might be A,E,D,B,C and for R2's values, it might be D,E,B,A,C. I should be able to click on a row index (first column in that row) and see my columns reordered. (Default is rows being reordered)
Update: I found this example for horizontal sorting Sorting Table Columns with jQuery Table Sorter, but how do I get this to work with datatables?
Upvotes: 0
Views: 1217
Reputation: 167
Thanks to Stryder for his solution above, without which I wouldn't have gotten this far.
Adding to it, to process non-integer data in the columns (decimals and strings), to have toggled sorting and to keep the first column static (similar to the header columns), I have refined the code to
var currRow = "";
var currOrd = "";
var table = $('#example').DataTable({
colReorder: true
});
table.on('click', 'td:first-of-type', function() {
var values = [];
var row = $(this).parent();
var valPos = [];
if (currRow != row.index()) { //if this row has not been sorted yet
currOrd = "desc";
currRow = row.index();
}
currOrd = (currOrd == "asc") ? "desc" : "asc"; //toggle sorting order
log("Sort row# " + (currRow + 1) + " in " + currOrd + " order");
row.children('td').each(function() {
values.push(this.innerHTML);
valPos.push(values.length - 1);
});
//remove logs :)
// log("initial values: " + values);
log("initial order: " + valPos);
// log("sorted values: " + sortWithIndeces(values));
sortWithIndeces(values)
log("new column order: " + values.sortIndices);
var colOrder = values.sortIndices;
table.colReorder.order(colOrder);
});
//get index after sort
//credit to:
//http://stackoverflow.com/questions/3730510/javascript-sort-array-and-return-an-array-of-indicies-that-indicates-the-positi
//and http://stackoverflow.com/questions/38076749/left-to-right-scrolling-on-datatable/38077921#38077921
function sortWithIndeces(toSort) {
var firCol = toSort[0];
for (var i = 1; i < toSort.length; i++) {
toSort[i] = [toSort[i], i];
}
toSort.sort(function(a, b) {
if ((a != firCol) && (b != firCol)) {
if (currOrd == "asc") {
if (($.isNumeric(a[0])) && ($.isNumeric(a[0]))) {
return a[0] - b[0];
} else {
return ((a[0] > b[0]) ? 1 : ((a[0] < b[0]) ? -1 : 0));
}
} else //descending order
{
if (($.isNumeric(a[0])) && ($.isNumeric(a[0]))) {
return b[0] - a[0];
} else {
return ((b[0] > a[0]) ? 1 : ((b[0] < a[0]) ? -1 : 0));
}
}
} else
return 0;
});
toSort.sortIndices = [0];
for (var j = 1; j < toSort.length; j++) {
toSort.sortIndices.push(toSort[j][1]);
toSort[j] = toSort[j][0];
}
return toSort;
}
//throwaway :)
function log(s) {
$('.console').append(s + "<br/>");
}
jsFiddle: https://jsfiddle.net/rsreeram84/tnozsp5s/
Upvotes: 0
Reputation: 1421
you can use: columns().order()
var table = $('#example').DataTable();
table
.columns( '.status' )
.order( 'desc' )
.draw();
More info: https://datatables.net/reference/api/columns().order()
EDIT
You can achieve this by using the dataTables.colReorder.min.js plugin, you might want to disable the drag and drop initialy...in anycase:
var table = $('#example').DataTable({
colReorder: true
});
table.on('click', 'td:first-of-type', function() {
var values = [];
var row = $(this).parent();
row.children('td').each(function(i){
values.push($(this).text());
});
var colOrder = values.sortIndices;
table.colReorder.order(colOrder);
});
//get index after sort
//credit to this post:
//http://stackoverflow.com/questions/3730510/javascript-sort-array-and-return-an-array-of-indicies-that-indicates-the-positi
function sortWithIndeces(toSort) {
for (var i = 0; i < toSort.length; i++) {
toSort[i] = [toSort[i], i];
}
toSort.sort(function(a, b) {
return a[0] - b[0]
});
toSort.sortIndices = [];
for (var j = 0; j < toSort.length; j++) {
toSort.sortIndices.push(toSort[j][1]);
toSort[j] = toSort[j][0];
}
return toSort;
}
Full working example here: https://jsfiddle.net/qjp8Lnam/6/
Upvotes: 2