CODEWITHSUNDEEP
javascriptarraysmultidimensional-array
Alex
Alex

Reputation: 123

Use filter method on multidimensional arrays in JavaScript

Having a multidimensional array, I would like to filter it, so only the array which has a word ending with underscore '_' is left. I have already accomplished this task using loops. 

function searchNames( logins ){
   var arr = logins;
    var reg = /\w+_\b/;
    var newAr = [];

  for(var i = 0; i < arr.length; i++) {
    for(var x = 0; x < arr[i].length; x++){
       if(arr[i][x].match(reg)){
       newAr.push(arr[i])
       }
     }

   }
  return newAr;
}

Is there any way to do the same using Array.prototype.filter() method. According to MDN reference (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter) you can do similar things but I can`t figure out how to filter the arrays inside the array. All of my attempts to use filter method inside of another filter method failed.

Upvotes: 1

Views: 492

Answers (2)

The Dembinski
The Dembinski

Reputation: 1519

Just pass the filter method a useful block:

array = [["hello_","cat"],["dog","dog"]];

arrayTest = function(arr){
    resp = false;
    arr.forEach(function(str){
       if(str.slice(-1) === "_") resp = true;
    });
    return resp;
}

result = array.filter(arrayTest);

or if you're really married to your regex:

array = [["hello_","cat"],["dog","dog"]];
regex = /\w+_\b/;

arrayTest = function(arr){
    resp = false;
    arr.forEach(function(str){
       if(str.match(regex)) resp = true;
    });
    return resp;
}

result = array.filter(arrayTest);

Upvotes: 1

Denys S&#233;guret
Denys S&#233;guret

Reputation: 382150

You seem to want

var newArr = arr.filter(subArr => subArr.some(e=>/\w+_\b/.test(e)));

Upvotes: 0

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