Reputation: 752
I'm trying to extend the functionality of my serverside datatable. I pass some extra filters to my controller / datatable, which I use to filter results. Currently in my model I am testing whether the params are present or not before applying my scopes, but I'm not convinced this is the best way since I will have a lot of if/else scenario's when my list of filters grows. How can I do this the 'rails way'?
if params[:store_id].present? && params[:status].present?
Order.store(params[:store_id]).status(params[:status])
elsif params[:store_id].present? && !params[:status].present?
Order.store(params[:store_id])
elsif !params[:store_id].present? && params[:status].present?
Order.status(params[:status])
else
Order.joins(:store).all
end
ANSWER: Combined the answers into this working code:
query = Order.all
query = query.store(params[:store_id]) if params[:store_id].present?
query = query.status(params[:status]) if params[:status].present?
query.includes(:store)
Upvotes: 13
Views: 11764
Reputation: 3729
The top answer above worked for me. Here is an example of its' real-life implementation:
lessons = Lesson.joins(:member, :office, :group)
if @member.present?
lessons = lessons.where(member_id: @member)
end
if @office.present?
lessons = lessons.where(office_id: @office)
end
if @group.present?
lessons = lessons.where(group_id: @group)
end
@lessons = lessons.all
Upvotes: 1
Reputation: 2345
You could do it like this:
query = Order
query = query.store(params[:store_id]) if params[:store_id].present?
query = query.status(params[:status]) if params[:status].present?
query = Order.joins(:store) if query == Order
Alternatively, you could also just restructure the status
and store
scopes to include the condition inside:
scope :by_status, -> status { where(status: status) if status.present? }
Then you can do this instead:
query = Order.store(params[:store_id]).by_status(params[:status])
query = Order.joins(:store) unless (params.keys & [:status, :store_id]).present?
Upvotes: 19
Reputation: 7522
Since relations are chainable, it's often helpful to "build up" your search query. The exact pattern for doing that varies widely, and I'd caution against over-engineering anything, but using plain-old Ruby objects (POROs) to build up a query is common in most of the large Rails codebases I've worked in. In your case, you could probably get away with just simplifying your logic like so:
relation = Order.join(:store)
if params[:store_id]
relation = relation.store(params[:store_id])
end
if params[:status]
relation = relation.status(params[:status])
end
@orders = relation.all
Rails even provides ways to "undo" logic that has been chained previously, in case your needs get particularly complex.
Upvotes: 14