CODEWITHSUNDEEP
javascriptangularjsregex
Ruchi yadav
Ruchi yadav

Reputation: 243

Regular expression for alphanumeric in Angularjs

I want a regex for alphanumeric characters in angularJS, I've tried some regex like "(\d[a-z])" but they allow me to enter only number as well as only alphabets. But I want a regex which won't allow me to enter them.

Example: 121232, abchfe, abd()*, 42232^5$ are some example of invalid input. 12fUgdf, dGgs1s23 are some valid inputs.

Upvotes: 2

Views: 7358

Answers (4)

Skull
Skull

Reputation: 1252

try this one : ^(?=.*[a-zA-Z])(?=.*[0-9])[a-zA-Z0-9]+$

dGgs1s23-valid
12fUgdf-valid,
121232-invalid, 
abchfe-in valid,
 abd()*- invalid, 
42232^5$- invalid

Upvotes: 0

Shaishab Roy
Shaishab Roy

Reputation: 16805

You can try this one. this expression satisfied at least one number and one character and no other special characters

^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$

in angular can test like:

$scope.str = '12fUgdf';
var pattern = new RegExp('^(?=.*[0-9])(?=.*[a-zA-Z])([a-zA-Z0-9]+)$');
$scope.testResult = pattern.test($scope.str);

PLUNKER DEMO

Upvotes: 1

Arg0n
Arg0n

Reputation: 8423

This one requires atleast one of each (a-z, A-Z and 0-9):

^(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])([a-zA-Z0-9]+)$

Upvotes: 2

Slan
Slan

Reputation: 560

If you wanted to return a replaced result, then this would work:

var a = 'Test123*** TEST';
var b = a.replace(/[^a-z0-9]/gi,'');
console.log(b);

This would return:

Test123TEST

OR

/^([a-zA-Z0-9 _-]+)$/

the above regex allows spaces in side a string and restrict special characters.It Only allows a-z, A-Z, 0-9, Space, Underscore and dash.

Upvotes: 0

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