CODEWITHSUNDEEP
javaregexstringconditional-statementsnewline
NEO
NEO

Reputation: 399

Java String Wrapping:How do I wrap words in a String at New line character(\n)

We want to wrap the word in a string at New Line character(\n).Basically, We are pressing ENTER to start a new line.

that is Enter key to create a new line in Our message when pressed.

Input data :

String is captured in comment column. Comment column given is:

EDI ORDER-SAVE COMMENTS\nC3 Generic\nLOC 0833\nExpected arrival 01/07/2016\nOTYPE NE\nTRKPC 01 GM/00007643020008361321

We tried on it:

string s = "EDIORDER-SAVE COMMENTS C3 Generic LOC 0833 Expected arrival 01/07/2016  OTYPE NE TRKPC 01 GM/00007643020008361321"  ;

StringBuilder sb = new StringBuilder(s);

int i = 0;
while ((i = sb.indexOf(" ", i + 20)) != -1) {
    sb.replace(i, i + 1, "\n");
}

Expected data after transformation: linebreak is new line character

Long  String of Comment field  should Splits in 6 different lines 

EDI ORDER-SAVE COMMENTS

C3 Generic

LOC 0833

Expected arrival 01/07/2016

OTYPE NE

TRKPC 01 GM/00007643020008361321

Exact data after output look like :

SalesOrder    NComment                            SalesOrderLine                    StockCode
183590  EDI ORDER-SAVE COMMENTS                         1                                 
183590                                                  2                         abc-defg-13OZ-24              
183590  C3    Generic                                   37                                
183590  LOC 0833                                        38                                
183590  Expected arrival               01/07/2016       39                                
183590  OTYPE NE                                        40                                
183590  TRKPC 01 GM/00007643020008361321                51

Any help on it would be much appreciated !

Upvotes: 0

Views: 2406

Answers (2)

explv
explv

Reputation: 2759

I think something like this should work:

private String wrapComment(String comment, int length) {

    if(comment.length() <= length) return comment;

    StringBuilder stringBuilder = new StringBuilder(comment);

    int spaceIndex = -1;

    for(int i = 0; i < comment.length(); i ++) {

        if(i % length == 0 && spaceIndex > -1) {
            stringBuilder.replace(spaceIndex, spaceIndex+1, "\n");
            spaceIndex = -1;
        }

        if(comment.charAt(i) == ' ') {
            spaceIndex = i;
        }

        stringBuilder.append(comment.charAt(i));
    }

    return stringBuilder.toString();
}

Testing:

String comment = "EDI ORDER-SAVE COMMENTS C3 Generic LOC 0833 Expected arrival 01/07/2016  OTYPE NE TRKPC 01 GM/00007643020008361321";
System.out.println(wrapComment(comment, 30));

Output:

EDI ORDER-SAVE COMMENTS C3
Generic LOC 0833 Expected
arrival 01/07/2016  OTYPE NE TRKPC
01 GM/00007643020008361321

Upvotes: 1

markus_
markus_

Reputation: 572

Sorry, I don't really get what you want to achieve. Do you want to insert the break BEFORE the word which passes the 20th character?

    StringBuilder sb = new StringBuilder(s);
    int currentSpaceFound = sb.indexOf(" ");
    int i = 1;
    while (currentSpaceFound != -1) {
        int lastOccurence = currentSpaceFound;
        currentSpaceFound = sb.indexOf(" ", currentSpaceFound + 1);
        if (currentSpaceFound > (20 * i)) {
            sb.setCharAt(lastOccurence, '\n');
            i++;
        }
    }
    System.out.println(sb);

Upvotes: 1

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