CODEWITHSUNDEEP
phpphp-generators
EvilNabster
EvilNabster

Reputation: 516

Easier menu generation depended on session

I am making a menu for website language and it works but i think the way i am doing it is not the best way in case i add more languages in future. Maybe someone can show a better example. Here is a piece of what i've got.

if(isSet($_SESSION['lang'])) {
    $lang = $_SESSION['lang'];
    if ($lang == "en") {
        echo '<li class="">EN 
              <ul>
              <li class="submenu">RU</li>
              <li class="submenu">ES</li>
              <li class="submenu">GR</li>
              <li class="submenu">DE</li>
              </ul>
              </li>';
    }
    if ($lang == "de") {
        echo '<li class="">DE 
              <ul>
              <li class="submenu">RU</li>
              <li class="submenu">ES</li>
              <li class="submenu">GR</li>
              <li class="submenu">EN</li>
              </ul>
              </li>';
    }
    // and so on for every language.. 
}

Probably would be better doing some array and than foreach function, but i have no idea how to do that x,x way too confusing

Upvotes: 1

Views: 27

Answers (2)

al3x2ndru
al3x2ndru

Reputation: 648

I think something like this should be @ help, i defined an array for languages and anytime you need to add a language, you just added there.

$lang = $_SESSION['lang'];
$languages = array ("de" => "DE", "ru" => "RU", "en" => "EN");

foreach ($languages as $key=>$val) 
    if ($lang == $key) 
    {
        unset($languages[$key]);
        $main_lang = $val;
        }

echo "
<li class=\"\">$main_lang //main button
   <ul> // sub menu";
foreach ($languages as $language)
    echo "<li class=\"submenu\">$language</li>";
echo "
   </ul>
</li>";

Upvotes: 0

Jose Manuel Abarca Rodr&#237;guez
Jose Manuel Abarca Rodr&#237;guez

Reputation: 10381

If you want an array, it's possible to create a function, this function will get the language as parameter and display the options according to it :

<?php

function display ( $lang )
{ $arr = array( "en" => array( "RU","ES","GR","DE" ),
                "de" => array( "RU","ES","GR","DE" )
              );
  echo '<li class="">' .
       '<ul>';
  foreach ( $arr[ $lang ] as $item ) // DISPLAY THE OPTIONS.
    echo '<li class="submenu">' . $item . '</li>';
  echo '</ul>
        </li>';
}

display( "en" ); // DISPLAY OPTIONS FOR "EN".
display( "de" ); // DISPLAY OPTIONS FOR "DE".

?>

In the future, you may add more languages to the array.

To test it, copy-paste previous code in a file, save it as PHP and open it in your browser.

Upvotes: 0

Related Questions