CODEWITHSUNDEEP
javascripthtmlarrays
factor_za
factor_za

Reputation: 119

Generate a random number 4 times no repeating Javascript?

I am wanting to generate a random number between 1-100, but I am only wanting to generate those numbers once each time. I have a loop that runs 3 times to run the .Math and then push that into an array. But I dont want the situation where it generates the same number more than once.

I have put 21 in the allAnswers[] array as that is something that will stay consistent. Is there a way to generate and then check that array if that number exists and then run the .math again?

function buttonGenerator(){
    var allAnswers = [21],
        randomizer = [];

    // Generates 3 random answers
    for(a = 0 ; a < 3; a++) {
         wrongAnswers = Math.floor((Math.random() * 100) + 1);
         allAnswers.push(wrongAnswers);
    }

    // Generates random buttons while inputting the correct and incorrect answers randomly
    for(i = 0 ; i < 4; i++) {
        var buttonArea = $("#answerOptions");
        input = $('<button class="col-xs-6 btn btn-primary"></button>');
        input.appendTo(buttonArea);
    }

    shuffle(allAnswers);
    console.log(allAnswers);
}

buttonGenerator();

Upvotes: 0

Views: 51

Answers (1)

omarjmh
omarjmh

Reputation: 13896

Use indexOf to check if the array has the value before pushing:

if (allAnswers.indexOf(wrongAnswers) === -1) {
  allAnswers.push(wrongAnswers);
}

Upvotes: 1

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