CODEWITHSUNDEEP
pythondjangohttp-redirect
nihal111
nihal111

Reputation: 388

Django next with query parameters

My website has a list of pages that are under /record and available only with query parameters of type and id. Like so:

/record?type=poem&id=175

I am using the django next redirect to go from the login page to the previous page. I initially used href="{% url 'auth:login' %}?next={{ request.path }}" to redirect, but it didn't take the query parameters (i.e type and id). This takes the user to

/login/?next=/record

I then used href="'{% url 'auth:login' %}?next={{ request.path }}'+window.location.search". However, this doesn't work as well. This takes the user to

/login/?next=/record?type=poem&id=175

but it finally redirects to

/record

How do I redirect using next along with query parameters? Is this behavior not possible?

Upvotes: 2

Views: 4743

Answers (2)

M57
M57

Reputation: 175

You need to escape special characters in the URL, namely '?', '&' and '='. While there is django.utils.encoding.escape_uri_path, it doesn't escape the ampersand (&), which is a problem because it will be interpreted as the end of the next parameter and the beginning of another.

Instead, you can use urllib.parse.quote:

from urllib.parse import quote
current_url_escaped = quote(request.get_full_path())

and in the template:

href="{% url 'auth:login' %}?next={{ current_url_escaped }}

Upvotes: 4

Rahul Gupta
Rahul Gupta

Reputation: 47876

You can use HttpRequest.get_full_path() method along with urlencode template filter to get the current url along with the query string.

HttpRequest.get_full_path()
Returns the path, plus an appended query string, if applicable.

href="{% url 'auth:login' %}?next={{request.get_full_path|urlencode}}

Upvotes: 3

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