CODEWITHSUNDEEP
javascriptjavajqueryhtmlajax
subbu royal
subbu royal

Reputation: 624

how to get ajax response to trigger click

I have two forms for buy now and for pincode when I click buynow button sending request through ajax and same thing is done for pincode form also.

HTML

 <form method="POST" action="/cart/add" id="myForm"> 
  .....
  ....
  <input type="button"  class="buyNowBtn" id="btnBuyNow"/>
 </form>

 <form action="#">
     <input type="text" id="pinCheck" class="pinCheck" placeholder="enter pin code" />
     <button class="btn btn-info" id="pinCheckTest"> Check</button>
 </form>

In the same buynow click event I need to trigger a pincode submit button, so I did this

(document).on('click', '#btnBuyNow', function (e) {
    ....
    ....
    $("#pinCheckTest").trigger('click');
    ....

});

the above trigger event is successfully calling pincode click event

$('#pinCheckTest').click(function () {
  $.ajax({
    type: 'GET',
    url: url,
    success: function (output) {
        if (output == 'true') {
            }
       else{
        }
    }
});

but I need to get ajax response back to trigger event so that I can do some operation is it possible?

something like

 (document).on('click', '#btnBuyNow', function (e) {
    ....
    ....
    $var output=$("#pinCheckTest").trigger('click');//I need to get ajax response back to this click
    if(output=='true'){
           ......
      }else{
       .....
      }
    ....

});

Upvotes: 1

Views: 4388

Answers (2)

guest271314
guest271314

Reputation: 1

You can define a variable outside of both click handlers, when .trigger() is called, assign $.ajax() to variable, use .then() within first click handler to process results of $.ajax() call.

Note, included event.preventDefault() to prevent submission of <form>, as pointed out by @IsmailRBOUH

var dfd;
$(document).on('click', '#btnBuyNow', function (e) {
    e.preventDefault();
    ....
    ....
    $("#pinCheckTest").trigger('click');
    if (dfd) {
      dfd.then(function(output) {
        // do stuff with output
        console.log(output)
      })
    }
    ....

});

$('#pinCheckTest').click(function (e) {
  e.preventDefault();
  dfd = $.ajax({
    type: 'GET',
    url: url,
    success: function (output) {
      if (output == 'true') {}
      else{};
    }
  })

});


var dfd;

$("#first").click(function() {
  $("#second").trigger("click");
  if (dfd) {
    dfd.then(function(data) {
      alert(data)
    })
  }
})

$("#second").click(function() {
  // do ajax stuff
  dfd = $.when("second clicked")
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="first">first button</button>
<button id="second">second button</button>

Upvotes: 1

Ismail RBOUH
Ismail RBOUH

Reputation: 10450

Since you are binding the click event to a button inside form you have the prevent the default behaviour which is 'submit the form'. Change you code to :

$('#pinCheckTest').click(function (e) {
    e.preventDefault();
    //Your ajax call
});

Here is a demo to clarify the difference https://jsfiddle.net/qvjjo3jk/.

Update1:

Add an id to your form:

<form action="#" id="pinCheckForm">
     <input type="text" id="pinCheck" class="pinCheck" placeholder="enter pin code" />
     <button class="btn btn-info" id="pinCheckTest"> Check</button>
 </form>

Then:

$('#pinCheckForm').submit(function(e) {
    e.preventDefault();
    $.ajax({
        type: 'GET',
        url: url,
        data: $(this).serialize(), //Sends all form data
        success: function(output) {
            if (output == 'true') {} else {}
        }
    });
});

Upvotes: 1

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