Reputation: 55759
I expected the following to print 1 2 3
. But it prints 1 undefined 3
. What am I missing?
var p = Promise.resolve('2');
new Promise(resolve => { console.log('1'); resolve(); })
.then(p)
.then((result) => console.log(result, '3'));
Upvotes: 1
Views: 110
Reputation: 4597
You need to wrap the p
variable in an anonymous function
var p = Promise.resolve('2');
new Promise(resolve => { console.log('1'); resolve(); })
.then(() => p)
.then((result) => console.log(result, '3'));
Upvotes: 6