CODEWITHSUNDEEP
c++boost
feelfree
feelfree

Reputation: 11753

Why I cannot use std::find when the basic element in a container is a boost::tuple?

I give the following codes to make my question more clear:

    bool bFind;
    boost::tuple<int> abc;
    //int abc;
    std::vector<boost::tuple<int> > myArray;
    //std::vector<int> myArray;
    bFind = is_vector_contains(myArray,abc);

is_vector_contains is template function:

template<typename T>
    bool is_vector_contains(const std::vector<T> &vecArray, const T &element)
    {
        if(std::find(vecArray.begin(),vecArray.end(),element) == vecArray.end())
            return false;
        else
            return true;
    }

When I compile the above codes, I have the following compilation error:

Error   1   error C2678: binary '==' : no operator found which takes a left-hand operand of type 'const boost::tuples::tuple<T0>' (or there is no acceptable conversion)

Any ideas? I tried to define a equal operator in this way, but it did not succeed in compilation.

 bool operator == (const boost::tuple<int> &a, const boost::tuple<int> &b)
    {
        return true;
    }

Upvotes: 0

Views: 52

Answers (1)

juanchopanza
juanchopanza

Reputation: 227458

boost::tuple's comparison operators are defined in a separate header, which you must include:

#include <boost/tuple/tuple_comparison.hpp>

Upvotes: 1

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