Reputation: 2790
I am new with firebase, so don't be very strict... I have next database:
{"list":[
{
"id":0,
"name":"name",
"text":"text"
},
{
"id":1,
"name":"name",
"text":"text"
},
{
"id":2,
"name":"name",
"text":"text"
},
{
"id":3,
"name":"name",
"text":"text"
}
]
}
Here is my code for request:
FirebaseDatabase database = FirebaseDatabase.getInstance();
Query mQuery = database.getReference("list")
.child("id").startAt("2");
mQuery.addListenerForSingleValueEvent(eventListener);
but this request return null...
Will be glad any idea?
UPDATE
I need to get all items where id is bigger than asked one.
Upvotes: 3
Views: 577
Reputation: 418
Query mQuery = database.getReference("list") .child("id").startAt("2");
This query returns nodes at https://<YOUR_FIREBASE_APP>.firebaseio.com/list/id
which doesn't exist and so you get a null result.
Try this instead
Query mQuery = database.getReference("list").startAt("2");
Upvotes: 0
Reputation: 7720
You need to add an order-by method
Query mQuery = database.getReference("list")
.orderByChild("id").startAt(2);
It should work
Upvotes: 5