CODEWITHSUNDEEP
bash
Qwertuy
Qwertuy

Reputation: 198

Script that writes several scripts in Bash

I have a script which is something like:

for k in {1..100..1}
do
cat << EOF > script${k}.sh

  do some things

  cat << EOF > somefile
  text
  EOF

  do some things


EOF
done

So, briefly put, I want 100 scripts that looks like:

do some things

  cat << EOF > somefile
  text
  EOF

  do some things

The problem is that when I run this, Bash associates the first EOF with the third one and stops writing and it starts trying to run the next commands.

How can I fix this?

Thanks in advance!

EDIT: I corrected a typo pointed out by Aaron below. Also, I will expand a bit my original question. Following Aaron's indication, I used END for the first and last EOF. It works fine, but I still have some trouble. Being more specific, my code looks like this:

for k in {1..100..1}
do
cat << END > script${k}.sh

  mkdir folder${k}
  cd folder${k}

  cat << EOF > somefile
  text
  EOF

  for j in {1..80..1}
    cat << EOF > program${j}
       text
    EOF

execute some stuff

END
done

I guess you see the trouble. Now the code works almost fine. The problem is with the variables. The ${k} that are between the ENDs, in the script${k} are not corrected substituted by the corresponding number!

Thanks for all the help :-)

Upvotes: 0

Views: 44

Answers (1)

Aaron
Aaron

Reputation: 24802

EOF can be any token that will be found at the end of the heredoc, so you can use another one on the outer heredoc :

for k in {1..100..1}
do
cat << END > script${1}.sh
do some things

cat << EOF > somefile
text
EOF

do some things

END
done

A few additional notes :

  • you're not using $k, so you're basically overwriting the same file 100 times. Did you meant script${k}.sh rather than script${1}.sh ?

  • creating 100 versions of the same script seems useless, even if the script's behaviour depends on its name. Couldn't you instead pass parameters to an unique script?

Upvotes: 2

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