Reputation: 123
How to accomplish this:
1. lorem ipsum
2. lorem ipsum
2a. lorem ipsum
3. lorem ipsum
4a. lorem ipsum
html: (I cannot expose the text so I'm using lorem)
<ol>
<li>lorem ipsum 1</li> <--- 1
<li>lorem ipsum 2 </li> <--- 2
<li class="number-alpha">lorem ipsum 2a</li> <--- 2a
<li>lorem ipsum 3</li> <--- 3
<li class="number-alpha">lorem ipsum 4a</li> <--- 2a
</ol>
as you can see the 2a is a different situation then the 4a, but I need to solve both situations in one ordered list and use CSS instead of JS or Jquery. The reason why you have 2 and 2a is because 2a is an exceptional message of 2 for a different user. the reason why its 4a instead of 3a is because 4a isn't an exceptional message but its information for a different user (it needs to be shown in the same list)
Upvotes: 0
Views: 692
Reputation: 2096
this is what I came with (pretty proud of this one I gotta admit) :
ul {
counter-reset:yourCounter;
}
ul li {
list-style:none;
}
ul li:not(.sub) {
counter-increment:yourCounter;
}
ul li:before {
content:counter(yourCounter) ". ";
}
ul li.sub:before, ul li.subskip:before {
content:counter(yourCounter) "a. ";
}
<ul>
<li>lorem ipsum</li>
<li>lorem ipsum</li>
<li class="sub">lorem ipsum</li>
<li>lorem ipsum</li>
<li class="subskip">lorem ipsum</li>
</ul>
Upvotes: 1