CODEWITHSUNDEEP
phpregexlocalhost
Mortaza Faryabi
Mortaza Faryabi

Reputation: 99

this regex is true but does not work in localhost

i have a regex and I test it in regepr and regex101

but it is not work in localhost!(my xampp version in 7.0.6) my code is the following code

html.html

{block content
ddggggggggggggggg
/endcontent}

file.php

$pt="~\{\s*block\s*-?\s*(\w+)[\s+|\~](.*)\/end\1}~s";
#Blocks#
preg_match($pt, file_get_contents('html.html'),$match1);
print_r($match1);exit;

I am guessing the problem is \1 because the following code is work correctly

$pt="~\{\s*block\s*-?\s*(\w+)[\s+|\~](.*)\/endcontent}~s";
#Blocks#
preg_match($pt, self::$tmp,$match1);
print_r($match1);exit;

why first code is does not work in my localhost? do you know what is the problem?

html.html file is not static and maybe diffrent I need a dynamic regex such as first regex

Upvotes: 2

Views: 161

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627100

You need to use a single quoted literal to make \1 be treated as a backreference (otherwise, you need to double escape it).

Also, to match either 1+ whitespaces or a ~ you need to use grouping with parentheses, not a character class. Note that [\s+|\~] matches 1 character: a whitespace, a +, | or a ~, and I doubt you actually want that behavior.

Use

$s = "{block content\nddggggggggggggggg\n/endcontent}";
$pt='~\{\s*block\s*-?\s*(\w+)(\s+|\~)(.*)\/end\1}~s';
preg_match($pt, $s, $match1);
print_r($match1);

See the IDEONE demo

Upvotes: 2

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