CODEWITHSUNDEEP
javaandroidstring
erik4thewinners
erik4thewinners

Reputation: 209

Android EditText: Check if whitespace not at beginning or end

I have an input field where the user has to enter his forename and his surname. Now I want to check whether there is a whitespace which is neither at the beginning nor at the end of the input. Only in this case, a button is enabled.

Checking the whitespace is easy:

private EditText input;
input = (EditText) findViewById(R.id.input);  

if(input.getText().toString().contains(" ")) {
   button.setEnabled(true);
}

But how can I make sure that the whitespace is not at the beginning or end of the input?

Thanks for your help

Upvotes: 2

Views: 3187

Answers (5)

TenaciousD
TenaciousD

Reputation: 1

    eingabe.addTextChangedListener(new TextWatcher(){
       @Override
       public void onTextChanged(CharSequence s,int start,int before,int count){ }
       @Override
        public void beforeTextChanged(CharSequence s,int start,int count,int after){ }
       @Override
        public void afterTextChanged(Editable s){
           weiterFertig.setEnabled(
                   s.length()>0&&!s.toString().startsWith(" ")&&!s.toString().endsWith(" ")&&s.toString().contains(" ")
           )
           ;
       }
    });

Upvotes: 0

Darshan
Darshan

Reputation: 515

Try this.

String input = textview.getText().toString();

if(input.subString(1,input.length()-1).contains(" "))
    button.setEnabled(false);
else
    button.setEnabled(true);

Upvotes: 0

AhmadReza Payan
AhmadReza Payan

Reputation: 2271

Try this:

EDITED

String str = input.getText().toString();
if (str.contains(" ") && (!str.startsWith(" ") && !str.endsWith(" ")) )
    button.setEnabled(true);

Or

  if ( !(Character.isWhitespace(str.charAt(0)) && Character.isWhitespace(str.charAt(str.length()-1)) ) )
     button.setEnabled(true);

Also you can use a combination of trim() and contains:

if(str.trim().contains(" ")) 
  button.setEnabled(true);

Upvotes: 5

Mohammadreza Khatami
Mohammadreza Khatami

Reputation: 1332

You need to do something like this

code

if(input.getText().toString().substring(0,1).contains(" "))
    System.out.println("failed");
else if((input.getText().substring((input.getText().length() -1),(input.getText().toString().length())).contains(" ")))
    System.out.println("failed");
else
    System.out.println("success");

I hope this helps you

Upvotes: 0

Ali Bdeir
Ali Bdeir

Reputation: 4365

result = input.getText().toString();
if(result.subString(0,1) == " "){
...
   }
if(result.substring(result.length() - 0) == " "{
...
}

I hope this helps

Upvotes: -1

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