Reputation: 831
Hi i want to open excel file with xlsx extension with xlsx.js library. I can open file by html input but i want to open it by using file path.
I have this code extracted from xlsx.js demo:
function handleFile(e) {
rABS = false;
use_worker = false;
console.log(e);
var files = e.target.files;
var f = files[0]; {
var reader = new FileReader();
var name = f.name;
reader.onload = function (e) {
if (typeof console !== 'undefined')
console.log("onload", new Date(), rABS, use_worker);
var data = e.target.result;
console.log("target result >>>>>>>>> " + e.target.result);
if (use_worker) {
xw(data, process_wb);
} else {
var wb;
if (rABS) {
wb = X.read(data, {
type : 'binary'
});
} else {
var arr = fixdata(data);
wb = X.read(btoa(arr), {
type : 'base64'
});
}
process_wb(wb);
}
};
if (rABS)
reader.readAsBinaryString(f);
else
reader.readAsArrayBuffer(f);
}
}
I want something like this:
var file = new File([""],"C:\\Users\\PalFS\\Downloads\\Fiverr_Example_List (1).xlsx");
var data = file;
How to do this or how can i convert this file into arraybuffer like it is returned from, var data = e.target.result;.
Thanks
Upvotes: 0
Views: 5030
Reputation: 1
You could use --allow-file-access-from-files
flag at chrome, chromium with XMLHttpRequest
, .responseType
set to "arraybuffer"
to retrieve .xlsx
file from local filesystem as ArrayBuffer
; set new File()
data to returned ArrayBuffer
. Second parameter at new File()
constructor should set the .name
property of created file.
Launch /path/to/chrome --allow-file-access-from-files
var request = new XMLHttpRequest();
// may be necessary to escape path string?
request.open("GET", "C:\\Users\\PalFS\\Downloads\\Fiverr_Example_List (1).xlsx");
request.responseType = "arraybuffer";
request.onload = function () {
// this.response should be `ArrayBuffer` of `.xlsx` file
var file = new File(this.response, "Fiverr_Example_List.xlsx");
// do stuff with `file`
};
request.send();
Upvotes: 1