Milton
Milton

Reputation: 13

Passing arrays from C to Fortran without knowing the size?

I'm trying to pass a 3d dynamic arrays from C to Fortran. For example, the first time I call the function I use

 extern "C" Fun_(double X[], double Y[], double Z[],
                 int *Nx, int *Ny, int *Nz,
                 double F[][20][20]);

The second time I have to change it to

extern "C" Fun_(double X[], double Y[], double Z[],
                int *Nx, int *Ny, int *Nz,
                 double F[][10][40]);

and so on. The main code is

int main() {
char path[500],id_type[3];
char *dir_path, *file_path;      
Nx=10000,Ny=20,Nz=20; ----> or Ny=10,Nz=40;                                       
double X[Nx], Y[Ny], Z[Nz];
double F[Nx][20][20] --- > or F[Nx][10][40];
....}

The array changes 446 times. So, I have to change its size dynamically. Any suggestions? Thanks

The Fortran code is pretty long but here is the relevant part

SUBROUTINE  Fun(X,Y,Z,Nx,Ny,Nz,F)
integer :: Nx,Ny,Nz,inx,iny,inz
real(8) :: F(Nx,Ny,Nz)
real(8) :: X(Nx),Y(Ny),Z(Nz)
....

Upvotes: 1

Views: 244

Answers (1)

Craig Estey
Craig Estey

Reputation: 33631

Caveat: It's been a long time since I did fortran, but this is what I came up with.

The variable length arrays seem easy enough. But, C uses row-major order for its 2D [and higher] arrays. But, Fortran uses column-major order. So, either the C code or the Fortran code will need to be aware of this.

I've created two subroutines: subx which is native Fortran, column-major order. And, suby which is C compatible, row-major order.

Also, some test output is below. Because the arrays are created as C-compatible, row-major, only suby produces the expected output.

Side note: One of my references for this was: http://www.yolinux.com/TUTORIALS/LinuxTutorialMixingFortranAndC.html


Here's the C code:

#include <stdio.h>

void subx_(int *,int *,int *);
void suby_(int *,int *,int *);

void
dotest(int Dy,int Dx)
{
    int val = 0;

    int arr[Dy][Dx];

    for (int y = 0;  y < Dy;  ++y) {
        for (int x = 0;  x < Dx;  ++x)
            arr[y][x] = val++;
    }

    subx_(&Dy,&Dx,&arr[0][0]);
    suby_(&Dy,&Dx,&arr[0][0]);
}

int
main(void)
{

    printf("testing ...\n");
    dotest(3,4);
    dotest(6,5);

    return 0;
}

Here's the Fortran code:

! this uses column-major order -- _not_ C compatible
subroutine subx(Dy,Dx,arr)
integer :: Dy,Dx
integer :: arr(Dy,Dx)
integer :: x,y

    write(*,700) ""
700 format (a)
    write(*,800) "subx: Dy=",Dy," Dx=",Dx
800 format (a,i4,a,i4)

    do y = 1, Dy
        do x = 1, Dx

    write(*,900) "subx ",x,y,arr(y,x)
900 format (a,i8,i8,i8)

        end do
    end do

end subroutine subx

! this uses row-major order -- _is_ C compatible
subroutine suby(Dy,Dx,arr)
integer :: Dy,Dx
integer :: arr(Dx,Dy)
integer :: x,y

    write(*,700) ""
700 format (a)
    write(*,800) "suby: Dy=",Dy," Dx=",Dx
800 format (a,i4,a,i4)

    do y = 1, Dy
        do x = 1, Dx

    write(*,900) "suby ",x,y,arr(x,y)
900 format (a,i8,i8,i8)

        end do
    end do

end subroutine suby

Here's the program output:

testing ...

subx: Dy=   3 Dx=   4
subx        1       1       0
subx        2       1       3
subx        3       1       6
subx        4       1       9
subx        1       2       1
subx        2       2       4
subx        3       2       7
subx        4       2      10
subx        1       3       2
subx        2       3       5
subx        3       3       8
subx        4       3      11

suby: Dy=   3 Dx=   4
suby        1       1       0
suby        2       1       1
suby        3       1       2
suby        4       1       3
suby        1       2       4
suby        2       2       5
suby        3       2       6
suby        4       2       7
suby        1       3       8
suby        2       3       9
suby        3       3      10
suby        4       3      11

subx: Dy=   6 Dx=   5
subx        1       1       0
subx        2       1       6
subx        3       1      12
subx        4       1      18
subx        5       1      24
subx        1       2       1
subx        2       2       7
subx        3       2      13
subx        4       2      19
subx        5       2      25
subx        1       3       2
subx        2       3       8
subx        3       3      14
subx        4       3      20
subx        5       3      26
subx        1       4       3
subx        2       4       9
subx        3       4      15
subx        4       4      21
subx        5       4      27
subx        1       5       4
subx        2       5      10
subx        3       5      16
subx        4       5      22
subx        5       5      28
subx        1       6       5
subx        2       6      11
subx        3       6      17
subx        4       6      23
subx        5       6      29

suby: Dy=   6 Dx=   5
suby        1       1       0
suby        2       1       1
suby        3       1       2
suby        4       1       3
suby        5       1       4
suby        1       2       5
suby        2       2       6
suby        3       2       7
suby        4       2       8
suby        5       2       9
suby        1       3      10
suby        2       3      11
suby        3       3      12
suby        4       3      13
suby        5       3      14
suby        1       4      15
suby        2       4      16
suby        3       4      17
suby        4       4      18
suby        5       4      19
suby        1       5      20
suby        2       5      21
suby        3       5      22
suby        4       5      23
suby        5       5      24
suby        1       6      25
suby        2       6      26
suby        3       6      27
suby        4       6      28
suby        5       6      29

Upvotes: 2

Related Questions