Reputation: 3304
So the title is somewhat misleading... I'll keep this simple: I'm comparing these two data structures:
Don't worry about any of the other details of these data structures. This is the only functionality I'm concerned with for this testing.
In theory, the LL should be performing better. However, they're near identical in time tests involving 10, 100, 1000... up to 5,000,000 elements.
My gut feeling is that the heap is large. I think the data segment defaults to 10 MB on Redhat? I could be wrong. Anyway, realloc() is first checking to see if space is available at the end of the already-allocated contiguous memory location (0-[n-1]). If the n-th position is available, there is not a relocation of the elements. Instead, realloc() just reserves the old space + the immediately following space. I'm having a hard time finding evidence of this, and I'm having a harder time proving that this array should, in practice, perform worse than the LL.
Here is some further analysis, after reading posts below:
[Update #1] I've modified the code to have a separate list that mallocs memory every 50th iteration for both the LL and the Array. For 1 million additions to the array, there are almost consistently 18 moves. There's no concept of moving for the LL. I've done a time comparison, they're still nearly identical. Here's some output for 10 million additions:
(Array)
time ./a.out a 10,000,000
real 0m31.266s
user 0m4.482s
sys 0m1.493s
(LL)
time ./a.out l 10,000,000
real 0m31.057s
user 0m4.696s
sys 0m1.297s
I would expect the times to be drastically different with 18 moves. The array addition is requiring 1 more assignment and 1 more comparison to get and check the return value of realloc to ensure a move occurred.
[Update #2] I ran an ltrace on the testing that I posted above, and I think this is an interesting result... It looks like realloc (or some memory manager) is preemptively moving the array to larger contiguous locations based on the current size. For 500 iterations, a memory move was triggered on iterations: 1, 2, 4, 7, 11, 18, 28, 43, 66, 101, 154, 235, 358 Which is pretty close to a summation sequence. I find this to be pretty interesting - thought I'd post it.
Upvotes: 4
Views: 971
Reputation: 284816
What's the basis of your theory that the linked list should perform better for insertions at the end? I would not expect it to, for exactly the reason you stated. realloc
will only copy when it has to to maintain contiguity; in other cases it may have to combine free chunks and/or increase the chunk size.
However, every linked list node requires fresh allocation and (assuming double linked list) two writes. If you want evidence of how realloc
works, you can just compare the pointer before and after realloc
. You should find that it usually doesn't change.
I suspect that since you're calling realloc
for every element (obviously not wise in production), the realloc
/malloc
call itself is the biggest bottleneck for both tests, even though realloc
often doesn't provide a new pointer.
Also, you're confusing the heap and data segment. The heap is where malloced memory lives. The data segment is for global and static variables.
Upvotes: 0
Reputation: 24877
(Updated.) As others have noted, if there are no other allocations in between reallocs, then no copying is needed. Also as others have noted, the risk of memory copying lessens (but also its impact of course) for very small blocks, smaller than a page.
Also, if all you ever do in your test is to allocate new memory space, I am not very surprised you see little difference, since the syscalls to allocate memory are probably taking most of the time.
Instead, choose your data structures depending on how you want to actually use them. A framebuffer is for instance probably best represented by a contiguous array.
A linked list is probably better if you have to reorganise or sort data within the structure quickly.
Then these operations will be more or less efficient depending on what you want to do.
(Thanks for the comments below, I was initially confused myself about how these things work.)
Upvotes: 0
Reputation: 21258
The performance of an array-based solution expanded with realloc()
will depend on your strategy for creating more space.
If you increase the amount of space by adding a fixed amount of storage on each re-allocation, you'll end up with an expansion that, on average, depends on the number of elements you have stored in the array. This is on the assumption that realloc will need to (occasionally) allocate space elsewhere and copy the contents, rather than just expanding the existing allocation.
If you increase the amount of space by adding a proportion of your current number of elements (doubling is pretty standard), you'll end up with an expansion that, on average, takes constant time.
Upvotes: 1
Reputation: 86651
This is not a real life situation. Presumably, in real life, you are interested in looking at or even removing items from your data structures as well as adding them.
If you allow removal, but only from the head, the linked list becomes better than the array because removing an item is trivial and, if instead of freeing the removed item, you put it on a free list to be recycled, you can eliminate a lot of the mallocs needed when you add items to the list.
On the other had, if you need random access to the structure, clearly an array beats the linked list.
Upvotes: 0
Reputation: 215259
Assuming your linked list is a pointer to the first element, if you want to add an element to the end, you must first walk the list. This is an O(n)
operation.
Assuming realloc
has to move the array to a new location, it must traverse the array to copy it. This is an O(n)
operation.
In terms of complexity, both operations are equal. However, as others have pointed out, realloc
may be avoiding relocating the array, in which case adding the element to the array is O(1)
. Others have also pointed out that the vast majority of your program's time is probably spent in malloc
/realloc
, which both implementations call once per addition.
Finally, another reason the array is probably faster is cache coherency and the generally high performance of linear copies. Jumping around to erratic addresses with significant gaps between them (both the larger elements and the malloc
bookkeeping) is not usually as fast as doing a bulk copy of the same volume of data.
Upvotes: 1
Reputation: 6126
You're right, realloc will just increase the size of the allocated block unless it is prevented from doing so. In a real world scenario you will most likely have other objects allocated on the heap in between subsequent additions to the list? In that case realloc will have to allocate a completely new chunk of memory and copy the elements already in the list.
Try allocating another object on the heap using malloc for every ten insertions or so, and see if they still perform the same.
Upvotes: 7
Reputation: 10864
So you're testing how quickly you can expand an array verses a linked list?
In both cases you're calling a memory allocation function. Generally memory allocation functions grab a chunk of memory (perhaps a page) from the operating system, then divide that up into smaller pieces as required by your application.
The other assumption is that, from time to time, realloc() will spit the dummy and allocate a large chunk of memory elsewhere because it could not get contiguous chunks within the currently allocated page. If you're not making any other calls to memory allocation functions in between your list expand then this won't happen. And perhaps your operating system's use of virtual memory means that your program heap is expanding contiguously regardless of where the physical pages are coming from. In which case the performance will be identical to a bunch of malloc() calls.
Expect performance to change where you mix up malloc() and realloc() calls.
Upvotes: 3