Reputation: 662
I am posting data by this POST method or by the first answer to this question, posting the data to a spring servlet configured with:
@RequestMapping(value = "/insert", method = RequestMethod.POST, consumes = { MediaType.APPLICATION_JSON_VALUE })
@ResponseStatus(HttpStatus.OK)
public @ResponseBody String insert(String a) {
The servlet-method is called, but its parameter 'a' is null. Why?
Edit: The main method and the AsyncTask:
main method
ServerCaller serverCaller = new ServerCaller();
try {
serverCaller.execute(new URL("http://192.168.56.1:8080/SpringHibernateExample/insert"));
}
AsyncTask
package com.test.insert;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
import java.net.URL;
import java.net.URLEncoder;
import java.util.List;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONObject;
import android.os.AsyncTask;
public class ServerCaller extends AsyncTask<URL, Integer, Long> {
@Override
protected Long doInBackground(URL... params1) {
try {
POST(params1[0].toString());
}
catch (Exception e) {
Log.realException(e);
throw new RuntimeException(e);
}
return 22l;
}
private String getQuery(List<NameValuePair> params) throws UnsupportedEncodingException {
StringBuilder result = new StringBuilder();
boolean first = true;
for (NameValuePair pair : params) {
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(pair.getName(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(pair.getValue(), "UTF-8"));
}
return result.toString();
}
public static String POST(String url) {
InputStream inputStream = null;
String result = "";
try {
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url);
String json = "";
// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("name", "a");
jsonObject.accumulate("country", "b");
jsonObject.accumulate("twitter", "c");
// 4. convert JSONObject to JSON to String
json = jsonObject.toString();
// ** Alternative way to convert Person object to JSON string usin Jackson Lib
// ObjectMapper mapper = new ObjectMapper();
// json = mapper.writeValueAsString(person);
// 5. set json to StringEntity
StringEntity se = new StringEntity(json);
// 6. set httpPost Entity
httpPost.setEntity(se);
// 7. Set some headers to inform server about the type of the content
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
// 10. convert inputstream to string
if (inputStream != null)
result = convertInputStreamToString(inputStream);
else
result = "Did not work!";
}
catch (Exception e) {
Log.e(e.getLocalizedMessage());
}
// 11. return result
return result;
}
private static String convertInputStreamToString(InputStream inputStream) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
String line = "";
String result = "";
while ((line = bufferedReader.readLine()) != null)
result += line;
inputStream.close();
return result;
}
}
Upvotes: 0
Views: 627
Reputation: 2491
i think you pass a json object but you do not map it in spring. In Spring you have to create a class ie CustomClass with properties name, country, twitter
public class CustomClass{
private String name;
private String country;
private String twitter;
//getters and setters should be here
}
then the code in Spring should look like this
@RequestMapping(value = "/insert", method = RequestMethod.POST, consumes = { MediaType.APPLICATION_JSON_VALUE })
@ResponseStatus(HttpStatus.OK)
public @ResponseBody String insert(@RequestBody CustomClass cs) {
cs.getName();
Let me know if this helped
Upvotes: 2