Reputation: 4236
I am currently using matplotlib.pyplot
to visualize some 2D data:
from matplotlib import pyplot as plt
import numpy as np
A=np.matrix("1 2 1;3 0 3;1 2 0") # 3x3 matrix with 2D data
plt.imshow(A, interpolation="nearest") # draws one square per matrix entry
plt.show()
Now i moved the data from squares to rectangles, meaning i have two additional arrays, for example:
grid_x = np.array([0.0, 1.0, 4.0, 5.0]) # points on the x-axis
grid_x = np.array([0.0, 2.5, 4.0, 5.0]) # points on the y-axis
now i want a grid with rectangles:
(grid_x[i], grid_y[j])
(grid_x[i+1], grid_y[j+1])
A[i,j]
What is an easy way to plot the data on the new grid? imshow
seems to to be usable, i looked at pcolormesh
but its confusing with the grid as 2D array, using two matrices like np.mgrid[0:5:0.5,0:5:0.5]
for the regular grid and building something similiar for the irregular one.
What is an easy way for visualization of the rectangles?
Upvotes: 1
Views: 2092
Reputation: 4236
Here is a reusable function based on the code from @ophir-carmi:
import matplotlib.pyplot as plt
from matplotlib.patches import Rectangle
from matplotlib.collections import PatchCollection
import itertools
import numpy as np
def gridshow(grid_x, grid_y, data, **kwargs):
vmin = kwargs.pop("vmin", None)
vmax = kwargs.pop("vmax", None)
data = np.array(data).reshape(-1)
# there should be data for (n-1)x(m-1) cells
assert (grid_x.shape[0] - 1) * (grid_y.shape[0] - 1) == data.shape[0], "Wrong number of data points. grid_x=%s, grid_y=%s, data=%s" % (grid_x.shape, grid_y.shape, data.shape)
ptchs = []
for j, i in itertools.product(xrange(len(grid_y) - 1), xrange(len(grid_x) - 1)):
xy = grid_x[i], grid_y[j]
width = grid_x[i+1] - grid_x[i]
height = grid_y[j+1] - grid_y[j]
ptchs.append(Rectangle(xy=xy, width=width, height=height, rasterized=True, linewidth=0, linestyle="None"))
p = PatchCollection(ptchs, linewidth=0, **kwargs)
p.set_array(np.array(data))
p.set_clim(vmin, vmax)
ax = plt.gca()
ax.set_aspect("equal")
plt.xlim([grid_x[0], grid_x[-1]])
plt.ylim([grid_y[0], grid_y[-1]])
ret = ax.add_collection(p)
plt.sci(ret)
return ret
if __name__ == "__main__":
grid_x = np.linspace(0, 20, 21) + np.random.randn(21)/5.0
grid_y = np.linspace(0, 18, 19) + np.random.randn(19)/5.0
grid_x = np.round(grid_x, 2)
grid_y = np.round(grid_y, 2)
data = np.random.randn((grid_x.shape[0] -1) * (grid_y.shape[0] -1))
fig = plt.figure()
ax = fig.add_subplot(111)
gridshow(grid_x, grid_y, data, alpha=1.0)
plt.savefig("test.png")
I am not totally sure about the performance for large grids and if the **kwargs
should be applied on PatchCollection
. And between some rectangles seems to be 1px whitespace, probably due to bad rounding. Maybe the dx, width, height
need a consistent floor
/ ceil
to the next full pixel.
Another solution using rtree
and imshow
:
import matplotlib.pyplot as plt
import numpy as np
from rtree import index
def gridshow(grid_x, grid_y, data, rows=200, cols=200, eps=1e-3, **kwargs):
grid_x1, grid_y1 = np.meshgrid(grid_x, grid_y)
grid_x2 = grid_x1[:-1, :-1].flat
grid_y2 = grid_y1[:-1, :-1].flat
grid_x3 = grid_x1[1:, 1:].flat
grid_y3 = grid_y1[1:, 1:].flat
grid_j = np.linspace(grid_x[0], grid_x[-1], cols)
grid_i = np.linspace(grid_y[0], grid_y[-1], rows)
j, i = np.meshgrid(grid_j, grid_i)
i = i.flat
j = j.flat
im = np.empty((rows, cols), dtype=np.float64)
idx = index.Index()
for m, (x0, y0, x1, y1) in enumerate(zip(grid_x2, grid_y2, grid_x3, grid_y3)):
idx.insert(m, (x0, y0, x1, y1))
for k, (i0, j0) in enumerate(zip(i, j)):
ind = next(idx.intersection((j0-eps, i0-eps, j0+eps, i0+eps)))
im[np.unravel_index(k, im.shape)] = data[np.unravel_index(ind, data.shape)]
fig = plt.gca()
return plt.imshow(im, interpolation="nearest")
if __name__ == "__main__":
grid_x = np.linspace(0, 200, 201) + np.random.randn(201)/5.0
grid_y = np.linspace(0, 108, 109) + np.random.randn(109)/5.0
grid_x = np.round(grid_x, 2)
grid_y = np.round(grid_y, 2)
data = np.random.randn((grid_x.shape[0] -1) * (grid_y.shape[0] -1))
fig = plt.figure()
ax = fig.add_subplot(111)
gridshow(grid_x, grid_y, data, alpha=1.0)
plt.savefig("test.png")
Upvotes: 1
Reputation: 2931
import matplotlib.pyplot as plt
from matplotlib.patches import Rectangle
import matplotlib.cm as cm
from matplotlib.collections import PatchCollection
import numpy as np
A = np.matrix("1 2 1;3 0 3;1 2 0;4 1 2") # 4x3 matrix with 2D data
grid_x0 = np.array([0.0, 1.0, 4.0, 6.7])
grid_y0 = np.array([0.0, 2.5, 4.0, 7.8, 12.4])
grid_x1, grid_y1 = np.meshgrid(grid_x0, grid_y0)
grid_x2 = grid_x1[:-1, :-1].flat
grid_y2 = grid_y1[:-1, :-1].flat
widths = np.tile(np.diff(grid_x0)[np.newaxis], (len(grid_y0)-1, 1)).flat
heights = np.tile(np.diff(grid_y0)[np.newaxis].T, (1, len(grid_x0)-1)).flat
fig = plt.figure()
ax = fig.add_subplot(111)
ptchs = []
for x0, y0, w, h in zip(grid_x2, grid_y2, widths, heights):
ptchs.append(Rectangle(
(x0, y0), w, h,
))
p = PatchCollection(ptchs, cmap=cm.viridis, alpha=0.4)
p.set_array(np.ravel(A))
ax.add_collection(p)
plt.xlim([0, 8])
plt.ylim([0, 13])
plt.show()
Here is another way, using image and R-tree and imshow
with colorbar
, you need to change the x-ticks
and y-ticks
(There are alot of SO Q&A about how to do it).
from rtree import index
import matplotlib.pyplot as plt
import numpy as np
eps = 1e-3
A = np.matrix("1 2 1;3 0 3;1 2 0;4 1 2") # 4x3 matrix with 2D data
grid_x0 = np.array([0.0, 1.0, 4.0, 6.7])
grid_y0 = np.array([0.0, 2.5, 4.0, 7.8, 12.4])
grid_x1, grid_y1 = np.meshgrid(grid_x0, grid_y0)
grid_x2 = grid_x1[:-1, :-1].flat
grid_y2 = grid_y1[:-1, :-1].flat
grid_x3 = grid_x1[1:, 1:].flat
grid_y3 = grid_y1[1:, 1:].flat
fig = plt.figure()
rows = 100
cols = 200
im = np.zeros((rows, cols), dtype=np.int8)
grid_j = np.linspace(grid_x0[0], grid_x0[-1], cols)
grid_i = np.linspace(grid_y0[0], grid_y0[-1], rows)
j, i = np.meshgrid(grid_j, grid_i)
i = i.flat
j = j.flat
idx = index.Index()
for m, (x0, y0, x1, y1) in enumerate(zip(grid_x2, grid_y2, grid_x3, grid_y3)):
idx.insert(m, (x0, y0, x1, y1))
for k, (i0, j0) in enumerate(zip(i, j)):
ind = next(idx.intersection((j0-eps, i0-eps, j0+eps, i0+eps)))
im[np.unravel_index(k, im.shape)] = A[np.unravel_index(ind, A.shape)]
plt.imshow(im)
plt.colorbar()
plt.show()
Upvotes: 1