Reputation: 367
Having fun with boost::hana. I wish to check for a specific nested type that acts like a tag in another type, so I borrow from hana::when_valid example and defined a class is_S along with its SFINAE-enabled specialization:
#include <iostream>
#include <boost/hana/core/when.hpp>
namespace hana = boost::hana;
#define V(x) std::cout << x << std::endl
struct S_tag { };
struct S {
using tag = S_tag;
};
struct T {
using tag = int;
};
template< typename T, typename = hana::when< true > >
struct is_S {
static constexpr bool value = false;
};
template< typename T >
struct is_S< T, hana::when_valid< typename T::tag > > {
static constexpr bool value = std::is_same<
typename T::tag, S_tag >::value;
};
int main () {
std::cout << "is_S ( S { }) = "; V ((is_S< S >::value));
std::cout << "is_S ( T { }) = "; V ((is_S< T >::value));
std::cout << "is_S (float { }) = "; V ((is_S< float >::value));
return 0;
}
This prints:
$ clang++ -std=c++1z sfinae.cpp && ./a.out | c++filt
is_S ( S { }) = 1
is_S ( T { }) = 0
is_S (float { }) = 0
Is there a simpler/shorter/more succinct way of writing the same check, in keeping with value-type computation of hana philosophy?
Upvotes: 1
Views: 285
Reputation: 3093
Here's what I might write:
#include <boost/hana.hpp>
#include <iostream>
namespace hana = boost::hana;
struct S_tag { };
struct S { using tag = S_tag; };
struct T { using tag = int; };
auto tag_of = [](auto t) -> hana::type<typename decltype(t)::type::tag> {
return {};
};
auto is_S = [](auto t) {
return hana::sfinae(tag_of)(t) == hana::just(hana::type<S_tag>{});
};
int main() {
std::cout << "is_S ( S { }) = " << is_S(hana::type<S>{})() << std::endl;
std::cout << "is_S ( T { }) = " << is_S(hana::type<T>{})() << std::endl;
std::cout << "is_S (float { }) = " << is_S(hana::type<float>{})() << std::endl;
}
Upvotes: 3
Reputation: 275810
I woukd be tempted by:
template<class...T>
constexpr std::integral_constant<bool,false> is_S(T const&...){ return {}; }
template<class T>
constexpr
std::integral_constant<bool,std::is_same<typename T::tag,S_tag>{}>
is_S(T const&){ return {}; }
Upvotes: 1