CODEWITHSUNDEEP
swiftios7
user5194501
user5194501

Reputation:

Delaying an action

I have UIView A and UIView B. A is a subview of a scrollView along with siblings subviews C-Z. B has a UILongPressGestureRecognizer and can be dragged around. If B is dragged inside A or C-Z I have function that does something. However, I want that function to go off only when B has been inside A for 1 second. If B is not inside A after that second I don't want anything to happen. How can I achieve this? I've already tried using an NSTimer. 

timer = NSTimer()
timer.scheduledTimerWithInterval(1.0,target:self,  #selector(fireMethod),userInfo:nil, repeats:Yes)

It seemed to work once, but after that first time, it never worked again.

Upvotes: 0

Views: 63

Answers (3)

Vakas
Vakas

Reputation: 6462

Try this Swift 3.0

func delayWithSeconds(_ seconds: Double, completion: @escaping () -> ()) {
    DispatchQueue.main.asyncAfter(deadline: .now() + seconds) { 
        completion()
    }
}

Usage

delayWithSeconds(1) {
   //Do something
}

Upvotes: 1

R.Sivavignesh
R.Sivavignesh

Reputation: 11

Try this code.

[self performSelector:@selector(yourAction:) withObject:nil afterDelay:2.3];//give delay asper your requirement.

-(void)yourAction
{
//your reuire code after delay.
}

Upvotes: 0

Konsy
Konsy

Reputation: 306

Create a delay function like so

func delay(delay:Double, closure:()->()) {

    dispatch_after(
        dispatch_time( DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC))), dispatch_get_main_queue(), closure)


}

Then in your UILongPressGestureRecognizer call the function as so

self.delay(1)
{
  //code here
}

Upvotes: 0

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