CODEWITHSUNDEEP
arraysswift
Jake
Jake

Reputation: 39

apple swift - referencing an array from a variable

newbie to swift, a contrived example. I have an array of menu categories, which in turn have menu items I want to loop through the categories and then read the elements of the sub-array of items. Don't know the syntax to reference the element as an array

ERROR at line 10, col 18: type 'String' does not conform to protocol 'Sequence' for (item) in offering {

var menuOffering = ["drinks" , "breakfastEntree"]
var drinks: Set = ["water","milk","coffee","tea","diet coke"]
var breakfastEntree: Set  = ["eggs", "bacon", "sausage","pancakes"]




for ( offering) in menuOffering {
    print ("\(offering)")
   for (item) in offering {   ERROR
       print ("\(item)")
    }

}

Upvotes: 2

Views: 71

Answers (2)

andrewcar
andrewcar

Reputation: 422

menuOffering is an Array of Sets. Without the quotes, the variable names now access the sets' contained values and they can be iterated over in the nested form you'll see below.

let drinks: Set = ["water", "milk", "coffee", "tea", "diet coke"]
let breakfastEntree: Set = ["eggs", "bacon", "sausage", "pancakes"]

let menuOffering = [drinks, breakfastEntree]

for offering in menuOffering {
    for item in offering {
       print(item) 
    }
}

You can also print variables out I did above if you are not trying to include a variable name in a String as below:

print("string: \(variableName)")

Make sure not to include a space between "print" and the parentheses.

Upvotes: 1

triandicAnt
triandicAnt

Reputation: 1378

menuOffering is a String array because you have defined it in quotes. In this case drinks and breakfastEntree. So you are trying to iterate over a String and getting error. Instead, define your array menuOffering as follow:

var menuOffering = [drinks , breakfastEntree] // without quotes

Now it will be array of sets. You modified code should be :

var drinks: Set = ["water","milk","coffee","tea","diet coke"]
var breakfastEntree: Set  = ["eggs", "bacon", "sausage","pancakes"]

var menuOffering = [drinks , breakfastEntree]

for ( offering) in menuOffering {
   for (item) in offering {
       print ("\(item)")
    }

}

Upvotes: 6

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