CODEWITHSUNDEEP
javastringreplace
Michael
Michael

Reputation: 127

How to replace a specific string in Java?

I usually don't ask for help but here I really need it.
I have the following code example:

String text = "aa aab aa aab";
text = text.replace("aa", "--");
System.out.println(text);

Console output: -- --b -- --b

I have a question, how do I only replace aa parts of the string not aab included.
So the console output is:

-- aab -- aab

I have another example:

String text = "111111111 1";
text = text.replace("1", "-");
System.out.println(text);

Console output: --------- -

I only want to replace a single character, not all the same ones who are placed together.
So the console output is:

111111111 -

Are there any Java shortcuts for situations like these? I can't figure it out, how to only replace specific part of the string.
Any help would be appreciated :)

Upvotes: 3

Views: 135

Answers (3)

Madan Reddy
Madan Reddy

Reputation: 85

We can use the StringTokenizer present in Java to acheive the solution for any kind of input. Below is the sample solution,

public class StringTokenizerExample {

/**
 * @param args
 */
public static void main(String[] args) {
    String input = "aa aab aa aab";
    String output = "";
    String replaceWord = "aa";
    String replaceWith = "--";
    StringTokenizer st = new StringTokenizer(input," ");
    System.out.println("Before Replace: "+input);
    while (st.hasMoreElements()) {
        String word = st.nextElement().toString();
        if(word.equals(replaceWord)){
            word = replaceWith;
            if(st.hasMoreElements()){
                word = " "+word+" ";
            }else{
                word = " "+word;
            }
        }
        output = output+word;
    }
    System.out.println("After Replace: "+output);
}

Upvotes: 0

Dici
Dici

Reputation: 25980

You can use a regex

String text = "111111111 1";
text = text.replaceAll("1(?=[^1]*$)", "");
System.out.println(text);

Explanation:

  • String.replaceAll takes a regex contrarily to String.replace which takes a litteral to replace
  • (?=reg) the right part of the regex must be followed by a string matching the regex reg, but only the right part will be captured
  • [^1]* means a sequence from 0 to any number of characters different from '1'
  • $ means the end of the string is reached

In plain english, this means: Please replace by an empty string all the occurrences of the '1' character followed by any number of characters different from '1' until the end of the string.

Upvotes: 0

Elliott Frisch
Elliott Frisch

Reputation: 201517

You could use a regular expression with String.replaceAll(String, String). By using word boundaries (\b), something like

String[] texts = { "aa aab aa aab", "111111111 1" };
String[] toReplace = { "aa", "1" };
String[] toReplaceWith = { "--", "-" };
for (int i = 0; i < texts.length; i++) {
    String text = texts[i];
    text = text.replaceAll("\\b" + toReplace[i] + "\\b", toReplaceWith[i]);
    System.out.println(text);
}

Outputs (as requested)

-- aab -- aab
111111111 -

Upvotes: 1

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