CODEWITHSUNDEEP
cstringmemory-management
Anne Nonimus
Anne Nonimus

Reputation: 669

Static C string allocation question

Consider the following code:

char* str = "Hello World";
memcpy(str, "Copy\0", 5);

A segmentation fault occurs during the memcpy. However, using this code:

char str[12];
memcpy(str, "Hello World\0", 12);
memcpy(str, "Copy\0", 5);

The program does not produce a segmentation fault.

Does the problem arise from allocating the memory on the stack versus the data section?

Upvotes: 5

Views: 18935

Answers (2)

user3458
user3458

Reputation: 

char* str = "Hello World";

and 

char str[12];

are two very different things. One allocates a pointer on the stack and an array in read-only "code segment". The pointer then points at the array. The other allocates the entire array on the stack, and there is no pointer.

Upvotes: 2

Mark Byers
Mark Byers

Reputation: 838296

When you use a string literal in gcc the value is placed in read-only memory and cannot be modified. Trying to modify it leads to undefined behaviour. Usually you will get a segmentation fault on Linux when you try to do this.

The second example works because you aren't modifying the string literal, you are modifying a copy of it that is stored in variable that is not read-only.

Upvotes: 14

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