CODEWITHSUNDEEP
grailsgroovy
Sayem
Sayem

Reputation: 713

Convert String to arrayList in groovy

I have a string like: String str = "[aa,bb,cc,dd]". I want to convert this to a list in groovy like [aa, bb, cc, dd]. Any groovy method available for this type conversion?

Upvotes: 4

Views: 21634

Answers (4)

injecteer
injecteer

Reputation: 20707

another way w/o replaceAll & tokenize:

def s = '[aa,bb,cc,dd]'
def a = []
s.eachMatch( /[\[]?([^\[\],]+)[,\]]?/ ){ a << it[ 1 ] }
assert '[aa, bb, cc, dd]' == a.toString()

Upvotes: 0

Gergely Toth
Gergely Toth

Reputation: 6976

Using regexp replaceAll

String str = "[aa,bb,cc,dd]"
def a = str.replaceAll(~/^\[|\]$/, '').split(',')
assert a == ['aa', 'bb', 'cc', 'dd']

EDIT:

The following version is a bit more verbose but handles extra white spaces

String str = " [ aa , bb , cc , dd ] "
def a = str.trim().replaceAll(~/^\[|\]$/, '').split(',').collect{ it.trim()}
assert a == ['aa', 'bb', 'cc', 'dd']

Upvotes: 9

Saurabh Gaur
Saurabh Gaur

Reputation: 23835

You should try as below :-

String str = "[aa,bb,cc,dd]"
assert str[1..str.length()-2].tokenize(',') == ['aa', 'bb', 'cc', 'dd']

Hope it helps..:)

Upvotes: 6

Opal
Opal

Reputation: 84864

Here you go:

String str= "['aa', 'bb', 'cc', 'dd']"
assert Eval.me(str) == ['aa', 'bb', 'cc', 'dd']

Eval is what you need.

Upvotes: 2

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