CODEWITHSUNDEEP
phpecho
alberzyzz
alberzyzz

Reputation: 277

Mistake in echo

Could someone tell me what fails in the following line: 

echo '<div id="login"><div id="centrar_app"><label>Success. Created account. <a href='login_app.php'>Log In</a></label></div></div>';

I know it must be a tiny stupid error, but I don't get it.

Thank you for your time

Upvotes: 1

Views: 57

Answers (4)

Deepak Dholiyan
Deepak Dholiyan

Reputation: 1912

You are mixing double quote with single quote, use below:-

 echo '<div id="login"><div id="centrar_app"><label>Success. Created account. <a href="login_app.php">Log In</a></label></div></div>';

You can use your current script with the php variable like below:- 

$login_url='login_app.php';

echo '<div id="login"><div id="centrar_app"><label>Success. Created account. <a href='.$login_url.'>Log In</a></label></div></div>';

Upvotes: 1

Maninder Singh
Maninder Singh

Reputation: 109

Try This:

<?php
echo '<div id="login"><div id="centrar_app"><label>Success. Created account. <a href="login_app.php">Log In</a></label></div></div>';

?>

Upvotes: 1

Devsi Odedra
Devsi Odedra

Reputation: 5322

Replace your code with this code, its just mistake of single quote**(')** and double quote**(")** 

echo '<div id="login"><div id="centrar_app"><label>Success. Created account. <a href="login_app.php">Log In</a></label></div></div>';

Upvotes: 1

Vinod VT
Vinod VT

Reputation: 7149

You are mixing single quotes and double quotes. href='login_app.php' change to href="login_app.php"

Try this, 

  echo '<div id="login"><div id="centrar_app"><label>Success. Created account. <a href="login_app.php">Log In</a></label></div></div>';

Upvotes: 1

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