CODEWITHSUNDEEP
c#xml
patel.milanb
patel.milanb

Reputation: 5992

how to get XML attribute using XmlSerializer in c#

I have this class and xml file which i am using to get the values.

XML file

<Task>
  <Employee Id="123">
    <string>/Name</string>
    <string>/Company</string>
  </Employee>

  <Manager Id="456">
    <string>/Name</string>
    <string>/Company</string>
  </Manager>
</Task>

Code

public class Task
{
    public List<string> Employee;
    public List<string> Manager;
}

var taks = (Task)new XmlSerializer(typeof(Task)).Deserialize(streamReader);

so, in tasks i am getting list of Employee with Name and Compnay as values correctly. I want to get the Id for each element. how do i get it?

/Name and /Company can be anything. I can put any value in there and I get it in employee without even creating a property for it. same goes for Manager as well, I can have /Email, /Website, /LastLogin etc and I get it in the Manager object without even creating a property for it.

appreciate your time and help.

Upvotes: 1

Views: 1224

Answers (1)

Timothy Ghanem
Timothy Ghanem

Reputation: 1616

Define your Task class as follows:

public class Task
{
    public Employee Employee;
    public Manager Manager;
}

Where Employee is:

public class Employee
{
    [XmlAttribute]
    public string Id {get;set;}

    public string Name{get;set;}

    public string Company{get;set;}
}

And Manager is:

public class Manager
{
    [XmlAttribute]
    public string Id {get;set;}

    public string Name{get;set;}

    public string Company{get;set;}
}

If you're interested in a generic list of properties for Employee and/or Manager, then consider having another class called Property as the following:

public class Property
{
     [XmlAttribute]
     public string Value{get;set;}
}

Then, change your Manager and Employee as the following:

public class Employee
{
    [XmlAttribute]
    public string Id {get;set;}

    public List<Property> Properties {get;set;}
}

public class Manager
{
    [XmlAttribute]
    public string Id {get;set;}

    public List<Property> Properties {get;set;}
}

Finally, change your XML as the following:

<Task>
  <Employee Id="123">
    <Properties>
       <Property Value="/Name" />
       <Property Value="/Company"/>
    </Properties>
  </Employee>

  <Manager Id="456">
    <Properties>
       <Property Value="/Name" />
       <Property Value="/Company"/>
    </Properties>
  </Manager>
</Task>

Upvotes: 3

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