CODEWITHSUNDEEP
phpiosswift
user4410354
user4410354

Reputation:

Could not post request in swift

I am trying post request in swift. I did successfully in objective-C but using swift I could not send request. $emailOK in PHP could not get information. where is the problem? thanks for helper. here is swift code

func httpPost1(url:String, postData: String, completion: String -> Void) {
        let request = NSMutableURLRequest(URL: NSURL(string: url)!)
        request.HTTPMethod = "POST"
        let postString = postData
        request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
        let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
            guard error == nil && data != nil else {                                                          // check for fundamental networking error
                print("error=\(error)")
                return
            }

            if let httpStatus = response as? NSHTTPURLResponse where httpStatus.statusCode != 200 {           // check for http errors
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(response)")
            }

            let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
            print("responseString = \(responseString)")
        }
        task.resume()
        }

here is excution code

httpPost1("xxxxx", postData: "emailOK=Hello") { result in

                print(result)//result is your string-response from server

            }

Here is my php code

<?php

$link = mysqli_connect($dbhost, $username, $dbpass, $database);

if (!$link) {
    echo "Error: Unable to connect to MySQL." . PHP_EOL;
    echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
    echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
    exit;
}

echo "Success: A proper connection to MySQL was made! The my_db database is great." . PHP_EOL;
echo "Host information: " . mysqli_get_host_info($link) . PHP_EOL;


$emailOK = isset($_GET["emailOK"]) ? $_GET["emailOK"] : '';

echo $emailOK;

$query = "INSERT INTO UserInfo VALUES ('', '$emailOK')";
mysqli_query($link, $query) or die (mysqli_error("error"));


mysqli_close($link);
?>

Upvotes: 0

Views: 113

Answers (5)

user4410354
user4410354

Reputation:

I found the problem, thanks for @OOPer comment. the problem is in PHP $emailOK = isset($_GET["emailOK"]) ? $_GET["emailOK"] : ''; It should be $emailOK = $_POST['emailOK'];

Upvotes: 1

shan
shan

Reputation: 134

    let dict = ["emailOK" : "Hello"]
    let jsonData = try! NSJSONSerialization.dataWithJSONObject(dict, options: NSJSONWritingOptions.PrettyPrinted)
    let jsonString = NSString(data: jsonData, encoding: NSUTF8StringEncoding)! as String
    let request = NSMutableURLRequest(URL: NSURL(string:"url")!)
    request.HTTPMethod = "POST"
    let postString = jsonString
    request.HTTPBody = postString.dataUsingEncoding(NSASCIIStringEncoding)
    let task = NSURLSession.sharedSession().dataTaskWithRequest(request) { data, response, error in
        guard error == nil && data != nil else {                                                          // check for fundamental networking error
            print("error=\(error)")
            return
        }

        if let httpStatus = response as? NSHTTPURLResponse where httpStatus.statusCode != 200 {           // check for http errors
            print("statusCode should be 200, but is \(httpStatus.statusCode)")
            print("response = \(response)")
        }

        let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
        print("responseString = \(responseString)")
    }
    task.resume()
}

Upvotes: 0

Igor Kislyuk
Igor Kislyuk

Reputation: 330

If you don't want to spend a lot of hours with useless efforts to write your successful get/post request, your best choice's to rely on libraries with all methods that you need.

In my humble opinion, I suggest you Alamofire https://github.com/Alamofire/Alamofire

Otherwise, to complete your request successfully you should specify Content-Type, Content-Type header information

Hope this helps you.

Upvotes: 0

fiks
fiks

Reputation: 1045

If you need to send the email as part of url, you should include it in URL:

var requestURL = url + "?" + postData

let request = NSMutableURLRequest(URL: NSURL(string: url)!)

But since you are sending a POST request, it's usually sent in HTTP body. Quite common way is to send it in JSON format:

let dict = ["emailOK" : "Hello"]
request.setValue("application/json", forHTTPHeaderField: "Content-Type")
do {
   request.HTTPBody = try NSJSONSerialization.dataWithJSONObject(dict, options: NSJSONWritingOptions.PrettyPrinted)
} catch _ {
   request.HTTPBody = nil
}

Upvotes: 0

Vishal Sonawane
Vishal Sonawane

Reputation: 2693

Try this code to create session object. I am not sure whether this will completely resolve your issue,but I think you should give it a try.

let config = NSURLSessionConfiguration.defaultSessionConfiguration()
let session = NSURLSession(configuration: config)

Upvotes: 0

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