CODEWITHSUNDEEP
c
Cenoc
Cenoc

Reputation: 11682

Conversion to short from char, odd results?

So my code has in it the following:

unsigned short num=0;
num=*(cra+3);
printf("> char %u\n",num);

cra is a char*

The problem is that it is getting odd output, sometimes outputting numbers such as 65501 (clearly not within the range of a char). Any ideas?

Thanks in advance!

Upvotes: 1

Views: 198

Answers (4)

user191776
user191776

Reputation:

cra is just a pointer.

It hasn't been allocated any space, by way of malloc or calloc. So its contents are undefined . *(cra + 3) will evaluate to the contents of the location 3 bytes ahead of the location cra (assuming char occupies 1 byte). I believe that its contents are also undefined.

unsigned short takes up 2 bytes, atleast on my system. Hence it can hold values from 0 to 65536. So, your output is within its defined range

Upvotes: 0

Chris
Chris

Reputation: 1

unsigned short has a range of (at least) 0 .. 65535 (link), the %u format specifier prints an unsigned int with a range of (commonly) 0 .. 4294967295. Thus, depending on the value of cra, the output appears to be completely sensible.

Upvotes: 0

kennytm
kennytm

Reputation: 523764

Apparently *(cra+3) is a char of value '\xdd'. Since a char is signed, it actually means -35 (0xdd in 2's complement), i.e. 0x...fffffdd. Restricting this to 16-bit gives 0xffdd, i.e. 65501.

You need to make it an unsigned char so it gives a number in the range 0–255:

num = (unsigned char)cra[3];

Note:
1. the signedness of char is implementation defined, but usually (e.g. in OP's case) it is signed.
2. the ranges of signed char, unsigned char and unsigned short are implementation defined, but again commonly they are -128–127, 0–255 and 0–65535 respectively.
3. the conversion from signed char to unsigned char is actually -35 + 65536 = 65501.

Upvotes: 6

caf
caf

Reputation: 239341

char is allowed to be either signed or unsigned - apparently, on your platform, it is signed.

This means that it can hold values like -35. Such a value not within the range representable by unsigned short. When a number out of range is converted to an unsigned type, it is brought into range by repeatedly adding or subtracting one more than the maximum value representable in that type.

In this case, your unsigned short can represent values up to 65535, so -35 is brought into range by adding 65536, which gives 65501.

Upvotes: 2

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