Reputation: 634
I am trying to set a linear gradient background over an image and my code works in Chrome but not in Safari. Here is a full example of my code:
HTML:
<div>
<img src="./assets/51a-front-img.png" draggable="false"/>
</div>
CSS:
div:after{
content: '\A';
position: absolute;
width: 100%;
height: 100%;
top:0;
background: rgba(0,0,0,0.5);
background: -moz-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.5)), color-stop(100%,rgba(0,0,0,0.7))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* W3C */
}
img {
position: relative;
width: 100%;
}
Upvotes: 7
Views: 19236
Reputation: 736
The div:after needs to be positioned on the left edge (which chrome does by default). change your css to:
div:after{
content: '\A';
position: absolute;
width: 100%;
height: 100%;
top:0;
left:0;
background: rgba(0,0,0,0.5);
background: -moz-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.5)), color-stop(100%,rgba(0,0,0,0.7))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(0,0,0,0.5) 0%,rgba(0,0,0,0.7) 100%); /* W3C */
}
img {
position: relative;
width: 100%;
}
Upvotes: 4