CODEWITHSUNDEEP
regexbashparsingsed
Wins
Wins

Reputation: 3460

Bash - Find and replace regex with another string

I have the following string libVersion = '1.23.45.6' and I need to replace 1.23.45.6 with 1.23.45.7.

Obviously the version could be any number with similar format (it does not have to be 4 numbers).

I tried to use the following but doesn't work

echo "libVersion = '1.23.45.6'" |sed "s/([0-9\.]+)/1.23.45.7/g"

Upvotes: 1

Views: 6692

Answers (1)

Avinash Raj
Avinash Raj

Reputation: 174844

Basic sed, ie sed without any arguments uses BRE (Basic Regular Expression). In BRE, you have to escape +, to bring the power of regex + which repeats the previous token one or more times, likewise for the capturing groups \(regex\)

echo "libVersion = '1.23.45.6'" | sed "s/[0-9.]\+/1.23.45.7/"

You may also use a negated char class to replace all the chars exists within single quotes.

echo "libVersion = '1.23.45.6'" | sed "s/'[^']*'/'1.23.45.7'/"

Since the replacement should occur only one time, you don't need a g global modifier.

Upvotes: 3

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