CODEWITHSUNDEEP
msbuild
Rob Scott
Rob Scott

Reputation: 8049

Possible to have (2) "conditions" in an MSBuild process

Somewhat new to MSBuild. I have a folder for robots.txt that uses the configuration to copy one of the files to the project's root folder. This is working as expected. However, when I want to run Debug it can't find the file, b/c obviously I don't need one for debugging. Instead of adding this dummy file, I wanted to exclude it from the build process if the configuration is one or the other listed, as so:

  <Target Name="AfterBuild">
    <Copy SourceFiles="Web.temp.config" DestinationFiles="Web.config" OverwriteReadOnlyFiles="True" />
    <Delete Files="Web.temp.config" />
    <Copy SourceFiles="$(ProjectDir)Content\robots\robots.$(Configuration).txt" Condition="$(Configuration)==Staging" DestinationFiles="robots.txt" OverwriteReadOnlyFiles="True" />
    <Copy SourceFiles="$(ProjectDir)Content\robots\robots.$(Configuration).txt" Condition="$(Configuration)==Production" DestinationFiles="robots.txt" OverwriteReadOnlyFiles="True" />
  </Target>

You can see above that I have (2) separate <Copy> elements that are doing the same thing (regarding the robots.txt files). Can I use an "OR" clause in this? And if so, how? Is there a better way to go about doing this?

Desired approach:

<Copy SourceFiles="$(ProjectDir)Content\robots\robots.$(Configuration).txt" Condition="$(Configuration)==Production || $(Configuration)==Staging" DestinationFiles="robots.txt" OverwriteReadOnlyFiles="True" />

Upvotes: 0

Views: 197

Answers (1)

Martin Ba
Martin Ba

Reputation: 38775

The MSbuild "or clause" is written as Or not as ||, otherwise your approach seems fine to me. (fwiw, I'm really not that versed in MSBuild.)

Also, the way I write conditions (though that may be partially cargo cult) is Condition="'$(Bla)' == 'Value'", i.e. I quote the values in the condition.

From your q text you also might try Condition="'$(Configuration)' != 'Debug'"?

Upvotes: 1

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