CODEWITHSUNDEEP
c++qtqstringqbytearray
JanSLO
JanSLO

Reputation: 388

Qt QString to QByteArray and back

I have a problem with tranformation from QString to QByteArray and then back to QString:

int main() {

    QString s;

    for(int i = 0; i < 65536; i++) {
        s.append(QChar(i));
    }

    QByteArray ba = s.toUtf8();

    QString s1 = QString::fromUtf8(ba);

    if(areSame(s, s1)) {
        qDebug() << "OK";
    } else {
       qDebug() << "FAIL";
       outputErrors(s, s1);
    }

    return 0;
}

As you can see I fill QString with all characters that are within 16bit range. and then convert them to QByteArray (Utf8) and back to QString. The problem is that the character with value 0 and characters with value larger than 55295 fail to convert back to QString.

If I stay within range 1 to < 55297 this test passes.

Upvotes: 6

Views: 7394

Answers (2)

mandroid
mandroid

Reputation: 187

I had a task to convert std::string to QString, and QString to QByteArray. Following is what I did in order to complete this task. 

std::string str = "hello world";

QString qstring = QString::fromStdString(str);

QByteArray buffer;

If you look up the documentation for "QByteArray::append", it takes QString and returns QByteArray. 

buffer = buffer.append(str);

Upvotes: 5

Ronald Klop
Ronald Klop

Reputation: 116

The characters from 55296 (0xD800) up to 57343 (0xdfff) are surrogate characters. You can see it as an escape character for the character after it. They have no meaning in itself.

You can check it by running:

// QChar(0) was omitted so s and s1 start with QChar(1)
for (int i = 1 ; i < 65536 ; i++)
{
    qDebug() << i << QChar(i) << s[i-1]  << s1[i-1] << (s[i-1] == s1[i-1]);
}

Upvotes: 3

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