CODEWITHSUNDEEP
python
Hossein Kianimehr
Hossein Kianimehr

Reputation: 11

How can I load a text file as array that can be loaded element by element?

I have a text file with the following information:

SHRO
BJRD
ZNJK
GRMI

I want to save them in a way that I can load them line by line. I mean, suppose its name is "name", and I want the 4th column like below:

name[3] = "GRMI"

How can I do this?

Upvotes: 0

Views: 70

Answers (2)

Amal Rajan
Amal Rajan

Reputation: 153

You could do something like this:

with open('filename.txt') as f:
    name = f.read().split()

EDIT
According to that answer you've posted, I understand that you simply need to print the name in a line and so, the modified code will be this:

with open('filename.txt') as f:
    print f.read().split('\n')[12][:4]     # Assuming that all of the those consist of 4 characters.
                                           # That number 12 was just an example.

Otherwise,

with open('filename.txt') as f:
    names = f.read().split('\n')
    print names[12].split()[0]            # Again, that number is an example.

Upvotes: 3

Jacob Bond
Jacob Bond

Reputation: 225

You probably want something like

with open('stationlist', 'r') as f:
    station_names = [line.split()[0] for line in f]

If all of the station names are four characters, the list comprehension could be replaced by

[line[:4] for line in f]

Upvotes: 0

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