Reputation:
I'm thinking about a certain kind of synchronisation primitive, but I don't know what this kind of synchronisation is called or if something like this would be working.
So there is one variable (boolean) which basically signals if one thread is still working on a block of memory or not. At the beginning the bool is set to false
, meaning the worker thread is not working on your block of memory. Now the main thread gives the worker thread a "todo-list", describing how it should be working on that block of memory. After that, it changes the state of the boolean to true
, so that the worker thread knows it is now allowed to do its work. The main thread can now continue its own work and checks at certain locations if the worker thread is now done working, e.g. if the boolean has been set to false
again. If it is stil true
, the main thread just continues its own work and doesn't wait for the worker thread. If the boolean is false
, the main thread knows the worker thread is done and starts processing the block of memory.
So the boolean just transfers the ownership over a block of memory between two threads. If one thread currently does not have the ownership of that memory, it just continues with its own work, and checks repeatedly if it now has the ownership again. This way, none of the threads is waiting for one another and can continue its own work.
What is this called and how is such a behavior implemented?
EDIT: Basically it's a mutex. But instead of waiting for the mutex to be unlocked again, it continues/skips the critical code.
Upvotes: 1
Views: 149
Reputation: 54589
What will you do if the main thread runs out of work?
Suppose you keep checking and you keep reading true
. Eventually you reach a point where the main thread cannot continue without the result from the worker thread. Since you have no more work to do, the only thing left is now keep checking the value of the flag over and over, wasting CPU resources that other threads could use to do useful work.
In general, this is not what you want. Instead, you would like the operating system to put your main thread to sleep and only wake it up once the worker thread has finished processing. All kinds of locks and semaphores that ship with modern operating systems work this way. Underneath there is some flag in memory that indicates who owns the lock, but there is also a bunch of logic around it that ensure the operating system won't schedule threads that have nothing to do but wait for a lock to become ready.
That being said, there are some situations where this is not what you want. If you are sufficiently sure that you won't run into the situation where one thread just spins on a lock, and you want to save the overhead that comes with the OS locks, just checking a flag like you described might be a viable option.
Note though that low-level stuff like this should be reserved for special circumstances, not be the first tool in your toolbox. It's just too easy to end up with an algorithm that is incorrect or an implementation that is not as efficient as you thought. If you decide to go down this road, be prepared to do some serious work to get it working as expected.
Upvotes: 0
Reputation: 26476
EDIT: Basically it's a mutex. But instead of waiting for the mutex to be unlocked again, it continues/skips the critical code.
It's still a mutex, just with "try" methods.
in standard C++, we're talking about std::mutex::try_lock
, which tries to lock the mutex, if it fails it returns false and moves on
class unlocker{
std::mutex& m_Parent;
public :
unlocker(std::mutex& parent) : m_Parent(parent){}
~unlocker() {m_Parent.unlock(); }
};
std::mutex mtx;
if (mtx.try_lock()){
unlocker unlock(mtx); // no, you can't use std::lock_guard/unique_lock here
//success, mtx is free
} else{
// do something else
}
on Native OS's code you have similar functions depending on the operating system you are on, like pthread_mutex_trylock
on Unix and TryEnterCriticalSection
on Windows. needless to say that standard mutex probably does use these functions behind the scenes
Upvotes: 1