Reputation: 616
I am using SQL Developer.
Table Name: PRCQA.PRCBUILD_FJ_BAT
Column Name: ETA
Value of 'ETA':
http://reefoats.us.oc.com:8080/atsresultviewer/displayresult?ree_run_id=153464685&type=ree
I am trying to extract the string 153464685
from the above resulting column and display it separately.
I have tried this till now:
SELECT SUBSTR(t.ETA, INSTR(t.ETA, '=')+1, INSTR(t.ETA, 'type')-1), t.ETA AS output
FROM PRCQA.PRCBUILD_FJ_BAT t
WHERE t.DTE_ID = '33782451' AND t.BAT_NAME LIKE '110_170_ECM 140_%'
I am getting the below value as result:
153464685&type=ree
But I want the result as: 153464685
Even if I change the INSTR(t.ETA, 'type')-1, still getting the same result?
What can I do here? Please suggest. Thanks.
Upvotes: 0
Views: 3025
Reputation: 1269563
Use regexp_substr()
:
select translate(regexp_substr(eta, '[=][^=&]+[&]', 1, 1), '=&a', 'a')
from PRCQA.PRCBUILD_FJ_BAT t
where t.DTE_ID = '33782451' and t.BAT_NAME like '110_170_ECM 140_%'
Upvotes: 1
Reputation: 616
This worked:
SELECT SUBSTR(t.ETA, INSTR(t.ETA, '=')+1, (INSTR(t.ETA, 'type')-INSTR(t.ETA, '='))-2), t.ETA AS output
FROM PRCQA.PRCBUILD_FJ_BAT t
WHERE t.DTE_ID = '33782451' AND t.BAT_NAME LIKE '110_170_ECM 140_%'
Upvotes: 0