CODEWITHSUNDEEP
swiftsprite-kitskaction
Drakalex
Drakalex

Reputation: 1538

Call a function which expects arguments with SKAction.runBlock()

I'm working with Swift and SpriteKit

I'd like to use SKAction.runBlock() to run a function that expect arguments :

class Tile : SKShapeNode
{
}

override func didMoveToView()
{
    let tile = Tile()
    tile.runAction(SKAction.runBlock(myFunc(tile)))
}

func myFunc(tile: Tile)
{
}

When I try to create a function that doesn't expect any argument, everything works fine, but the code above returns this:

Cannot convert value of type '()' to expected argument type 'dispatch_block_t' (aka '@convention(block) () -> ()')

What am I not understanding ?

Upvotes: 2

Views: 308

Answers (2)

OOPer
OOPer

Reputation: 47876

With writing this sort of expression:

SKAction.runBlock(myFunc(tile))

You are passing the result of calling myFunc(tile).

(I believe you do not think this code: SKAction.runBlock(sin(0)), would pass some sort of closure to runBlock.)

And the returned value from myFunc(tile) is a void value, as myFunc is declared to return nothing. A void value can be represented also as (). The error message says () cannot be converted to a closure of type @convention(block) () -> ().

Thus, you need to create a closure of type @convention(block) () -> ().

    tile.runAction(SKAction.runBlock({()->() in myFunc(tile)}))

in short:

    tile.runAction(SKAction.runBlock({myFunc(tile)}))

Upvotes: 4

Simone Pistecchia
Simone Pistecchia

Reputation: 2832

You are missing {} Just:

 tile.runAction(SKAction.runBlock({
    myFunc(tile)}))

Upvotes: 1

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