Reputation: 783
I have a number of nested loops with small sizes I, J, ... known at compile time, e.g.
for(int i = 0; i < I; ++i) {
for(int j = 0; j < J; ++j) {
// ...
// do sth with (i,j,...)
}
}
I need to unroll the loops using the sizes I, J, ... in such a way that I can use each coordinate combination at compile time.
To clarify, consider the following structure and take 2 nested loops with sizes I = 2, J = 3.
template<int... I>
struct C {
static void f() {
// do sth
}
};
I can not use the indices i, j (similar to above) to index the structure C since they are not known at compile time. However what I would like to generate is exactly what would have been the case had I been allowed to use the indices, e.g.
C<0,0>::f();
C<0,1>::f();
C<0,2>::f();
C<1,0>::f();
C<1,1>::f();
C<1,2>::f();
I am not particularly concerned with the order of call generations as long as all combinations are produced. The generation mechanism should generalize to arbitrary number of nested loops.
Upvotes: 9
Views: 591
Reputation: 65620
You can do this by instantiating templates in a tree-like manner, keeping track of the nodes currently visited.
namespace detail{
//This is used to store the visited nodes
template<int...> struct int_pack;
//Primary template
template<typename, int... I>
struct C;
//This is the leaf node
template<int... Is>
struct C<int_pack<Is...>> {
//The loop body goes here
static void f() {
std::cout << __PRETTY_FUNCTION__ << '\n';
}
};
//This is the recursive case
template <int I, int... Is, int... PIs>
struct C<int_pack<PIs...>, I,Is...> {
template <std::size_t... Idx>
static void f_help (std::index_sequence<Idx...>) {
//Store the current node in the pack
//and call `C::f` for each loop iteration
(void)std::initializer_list<int> {
(C<int_pack<PIs...,Idx>,Is...>::f(), 0)...
};
}
//Use tag dispatching to generate the loop iterations
static void f() {
f_help(std::make_index_sequence<I>{});
}
};
}
//Helper alias
template<int... Is>
using C = detail::C<detail::int_pack<>, Is...>;
Usage is pretty simple:
C<2,3>::f();
On Clang this prints:
static void detail::C<detail::int_pack<0, 0>>::f() [I = <>]
static void detail::C<detail::int_pack<0, 1>>::f() [I = <>]
static void detail::C<detail::int_pack<0, 2>>::f() [I = <>]
static void detail::C<detail::int_pack<1, 0>>::f() [I = <>]
static void detail::C<detail::int_pack<1, 1>>::f() [I = <>]
static void detail::C<detail::int_pack<1, 2>>::f() [I = <>]
You could make this more generic so that you can inject the loop body into the class through a lambda, but the above solution should do if you only want to do this once and don't want to pull in other dependencies like boost::hana
. Here's a possible implementation of the more generic version (you could improve it with perfect forwarding and the like):
namespace detail{
template<int...> struct int_pack;
template<typename, int... I>
struct C;
template<int... Is>
struct C<int_pack<Is...>> {
template <typename Func>
static void f(const Func& func) {
func(Is...);
}
};
template <int I, int... Is, int... PIs>
struct C<int_pack<PIs...>, I,Is...> {
template <std::size_t... Idx, typename Func>
static void f_help (std::index_sequence<Idx...>, const Func& func) {
(void)std::initializer_list<int>{ (C<int_pack<PIs...,Idx>,Is...>::f(func), 0)... };
}
template <typename Func>
static void f(const Func& func) {
f_help(std::make_index_sequence<I>{}, func);
}
};
}
You would use this like so:
C<2,3>::f([](int i, int j){
std::cout << "i " << i << " j " << j << '\n';
});
Here's a quick version I mocked up with boost::hana
. There are likely better ways to do this, but this should give you an idea of what can be done.
template <typename Func>
void unroll (const Func& func) {
func();
}
template <std::size_t I1, std::size_t... Is, typename Func>
void unroll (const Func& func) {
hana::for_each(hana::range_c<std::size_t, 0, I1>,
[&](auto x) {
unroll<Is...>([x, &func] (auto... xs) { func(x,xs...); });
});
}
Upvotes: 8