CODEWITHSUNDEEP
javahtmljspservletsjakarta-ee
blinkettaro
blinkettaro

Reputation: 361

Linking a servlet to a tab menu

I have a question about servlet/jsp/html. I have a tab menu:

<ul class="nav nav-pills">
    <li class="active"><a data-toggle="pill" href="#list">LIST OF PRODUCTS</a></li>
    <li><a data-toggle="pill" href="#add">ADD PRODUCT</a></li>
</ul>
  
<div class="tab-content">
   <div id="list" class="tab-pane fade in active">
      <h3>LIST OF PRODUCTS</h3>
      <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>
   </div>

   <div id="add" class="tab-pane fade">
      <h3>ADD PRODUCT</h3>
      <p>Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat.</p>
   </div>

I would like to link a servlet when I press a tab and consequently calling a jsp in the tab-content, instead of :

 <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.</p>

My servlet code : 

@WebServlet(name = "NewServlet", urlPatterns = {"/NewServlet"})
public class NewServlet extends HttpServlet {

@EJB
private BDBeanLocal bDBean;

/**
 * Processes requests for both HTTP <code>GET</code> and <code>POST</code>
 * methods.
 *
 * @param request servlet request
 * @param response servlet response
 * @throws ServletException if a servlet-specific error occurs
 * @throws IOException if an I/O error occurs
 */
protected void processRequest(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {

        ArrayList<Products> list = new ArrayList<Products>();
        list =  bDBean.listaProdotti();

        request.setAttribute("lista", list);

        String arg = "/" + this.getServletName() + ".jsp";
        RequestDispatcher dispatcher = this.getServletContext().getRequestDispatcher(arg);
        dispatcher.forward(request, response);


    }

    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        processRequest(request, response);
    }

    @Override
    public String getServletInfo() {
    return "Short description";
    }// </editor-fold>

}

and this is my web.xml

 <?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.1" xmlns="http://xmlns.jcp.org/xml/ns/javaee"         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd">
<servlet>
    <servlet-name>NewServlet</servlet-name>
    <servlet-class>servlet.NewServlet</servlet-class>
</servlet>
<servlet>
    <servlet-name>loginServlet</servlet-name>
    <servlet-class>servlet.loginServlet</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>NewServlet</servlet-name>
    <url-pattern>/NewServlet</url-pattern>
</servlet-mapping>
<servlet-mapping>
    <servlet-name>loginServlet</servlet-name>
    <url-pattern>/loginServlet</url-pattern>
</servlet-mapping>
<session-config>
    <session-timeout>30</session-timeout>
</session-config>

Upvotes: 0

Views: 1358

Answers (1)

Mohammadreza Khatami
Mohammadreza Khatami

Reputation: 1332

Make the hyperlink have a URL that you have a servlet mapping defined for in the web.xml file.

The servlet-mapping element defines a mapping between a servlet and a URL pattern. The example below maps the servlet named myservlet to any URL that starts with /foo:

<servlet>
   <servlet-name>myservlet</servlet-name>
   <servlet-class>com.foo.examples.MyServlet</servlet-class>
</servlet>
<servlet-mapping>
   <servlet-name>myservlet</servlet-name>
   <url-pattern>/anything/*</url-pattern>
</servlet-mapping>

For this example, a hyperlink such as <a href="/anything/test.html">Click Me</a> would invoke the servlet.

by url-pattern you said every request after /anything should handled by myservlet Servlet. and after that you use something(test.html) after your servlet as your defined in Servlet URL pattern to send a request to myservlet.

-----------

Another way to call a servlet is using parameters.

<a href="servletUrl?param=value">click</a>

I hope this helps you.

Upvotes: 1

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