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pythonstring-literalstimeit
Martin08
Martin08

Reputation: 21460

Tricky Python string literals in passing parameter to timeit.Timer() function

I'm having a hard time with the setup statement in Python's timeit.Timer(stmt, setup_stmt). I appreciate any help to get me out of this tricky problem:

So my sniplet looks like this:

def compare(string1, string2):
    # compare 2 strings

if __name__ = '__main__':
    str1 = "This string has \n several new lines \n in the middle"
    str2 = "This string hasn't any new line, but a single quote ('), in the middle"

    t = timeit.Timer('compare(p1, p2)', "from __main__ import compare; p1=%s, p2=%s" % (str1,str2))

I don't know how to escape the metacharacter in the variable str1, str2 without changing their meaning in the setup statement: 

"from __main__ import compare; p1=%s, p2=%s" % (str1,str2)

I tried various combination but always have the following errors: SyntaxError: can't assign to literal
SyntaxError: EOL while scanning single-quoted string
SyntaxError: invalid syntax

Upvotes: 6

Views: 5923

Answers (2)

Brian
Brian

Reputation: 119311

Why bother quoting the strings at all? Just use them directly. ie. change your last line to:

t = timeit.Timer('compare(str1, str2)', "from __main__ import compare, str1, str2")

Upvotes: 2

S.Lott
S.Lott

Reputation: 392012

Consider This as an alternative.

t = timeit.Timer('compare(p1, p2)', "from __main__ import compare; p1=%r; p2=%r" % (str1,str2))

The %r uses the repr for the string, which Python always quotes and escapes correctly.

EDIT: Fixed code by changing a comma to a semicolon; the error is now gone.

Upvotes: 7

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