Reputation: 33
I am defining a function to accept a matrix (2d array), for example x[][]
; and the function should print the biggest even number in each line
public static void biggestEvenNumOfEachLine(int x[][]){
int even,t=0,max;
int arr[] = new int [x.length];
for(int i = 0; i < x.length;i++){
for(int j = 0; j < x[i].length;j++,t++){
if(x[i][j] % 2 == 0){
even = x[i][j];
arr[j] = even;
}
}
}
}
What am I missing?
Upvotes: 3
Views: 66
Reputation: 201447
I would start by finding the biggest even number in a single line array. Start with the smallest possible value, and then iterate the array. Test for even, and then set the max
(and then return it). Something like,
private static int biggestEvenNum(int[] x) {
int max = Integer.MIN_VALUE;
for (int i = 0; i < x.length; i++) {
if (x[i] % 2 == 0) {
max = Math.max(max, x[i]);
}
}
return max;
}
But, in Java 8+, I would prefer to filter
for even values and get the max
like
private static int biggestEvenNum(int[] x) {
return IntStream.of(x).filter(v -> v % 2 == 0).max().getAsInt();
}
Then your method is as simple as iterating the line
(s) in your matrix, printing the result. Like,
public static void biggestEvenNumOfEachLine(int[][] x) {
for (int[] line : x) {
System.out.println(biggestEvenNum(line));
}
}
Upvotes: 2
Reputation: 841
public static void biggestEvenNumOfEachLine(int x[][])
{
int arr[] = new int [x.length];
for(int i = 0; i < x.length;i++)
for(int j = 0; j < x[i].length;j++)
if(x[i][j] % 2 == 0 && x[i][j] > arr[i]){
arr[i] = x[i][j];
System.out.println(arr[i]);
}
}
This will work but if there is no even number at particular line then corresponding number to that line will be zero.
Upvotes: 0